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7nadin3 [17]
3 years ago
15

Which of the following points is in the solution set of y > -x2 + 5?

Mathematics
2 answers:
sattari [20]3 years ago
7 0
Here is the graph remember that a dotted line means excluding those points

Nady [450]3 years ago
3 0

Answer: Hello!

the inequality is y > -x2 + 5, and the options are (0,5), (1,3) and (2,4) as i see in the coments.

we want to see wich of these options is a solution for our inequality.

remember that the notation is (x,y) so in the pair (0,5) x is equal to 0, and y is equal to 5.

then we replace tis values in the inequality and see if in remains true:

for (0,5)

5 > -0^2 + 5 = 5

5 > 5

this is false, because a number cant be bigger than itself, then (0,5) is not a solution.

for(1,3)

3 > -1^2 + 5 = 4

here again is false, because 3 isnt bigger than 4, then (1,3) is not a solution.

for (2,4)

4 > -2^2 + 5 = -4 + 5 = 1

here 4 > 1, wich is true!

then the pair (2,4) is a solution for our inequality.

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Find the equation of the line passing through the points (-2/3,1) and (-2,1/2). Write the equation in standard form.
7nadin3 [17]
Standard form is y = mx + b.
To find the slope, m, we must find the 'rise over run,' or the difference in y divided by the difference in x. We do this by:
\frac{y1 - y2}{x1 - x2}  =  \frac{ (-  \frac{2}{3} ) - ( -2 )}{(1) - ( \frac{1}{2} ) } =  \frac{ \frac{4}{3} }{ \frac{1}{2} } \\  =  \frac{4}{3}  \times  \frac{2}{1}  =  \frac{8}{3}
Therefore, the slope is 8/3.

To find b, we must plug in the slope and one point:
(1) = ( \frac{8}{3} )( -  \frac{2}{3} ) + b \\ 1 =  -  \frac{16}{9}  + b \\  \frac{25}{9}  = b
Therefore, b is 25/9, and the total equation is
y =  \frac{8}{3} x +  \frac{25}{9}
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