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3 years ago

Factorise this expression: 7y + 14

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

5 0

the ans is 7(y +2) because 7 is a factor of 14 and its seven y so u bring out 7 and leave y and 2

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13p + 5p - 9p -2p=7 what is p

Law Incorporation [45]

Answer:

p=1

Step-by-step explanation:

18p-9p=9p

9p-2p=7p

7p=7

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2 years ago

Graph the image of the given triangle under a dilation with a scale factor of 12 and center of dilation (0, 0)

AysviL [449]

Answer:Graph the image of the given triangle under a dilation with a scale factor of 12 and center of dilation (0, 0)

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3 years ago

A chef makes a fruit salad using pears and mangos. Pears and mangos each cost $2.25 per fruit. The chef buys x pears and y mango

GrogVix [38]

Answer:

P=2.25x-----------1

M=2.25y----------2

Step-by-step explanation:

Step one:

given data

we are told that the cost of pears= $2.25 each

and cost of mango= $2.25 each

Step two:

the chef bought x pears and y mangoes

let the total cost of pears be P

and for mango be M

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3 years ago

Find the equation of the line given the slope and the y-intercept

GREYUIT [131]

Answer:

y = $\frac{1}{2}x + 3$

Step-by-step explanation:

The equation for a linear graph is usually written in the following format...

y = mx + b

Where m would be the slope, usually referring to rise over run and b would be the y-intercept (where the line crosses the y-axis). From the graph, we can see that the line crosses the y-axis at point 3 so b would be 3. The graph also shows us that for every 1 value that the line rises it moves to the right 2 values. Therefore, the slope would be 1/2. Using these values we can create the following equation...

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3 years ago

A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa

PSYCHO15rus [73]

Answer:

A) $\dfrac{11}{23}$

B) $\dfrac{88}{345}$

Step-by-step explanation:

A survey of 46 college athletes found that

24 played volleyball,
22 played basketball.

A) If we pick one athlete survey participant at random, the probability they play basketball is

$P_1=\dfrac{22}{46}=\dfrac{11}{23}$

B) If we pick 2 athletes at random (without replacement),

the probability we get one volleyball player is $\dfrac{24}{46}=\dfrac{12}{23};$
the probability we get another basketball player is $\dfrac{22}{45}$ (only 45 athletes left).

Thus, the probability we get one volleyball player and one basketball player is

$P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}$

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3 years ago