A 3 diget number is written on paper .what is the probliblity it starts with 3

yulyashka [42]

Answer:

x = 5

Step-by-step explanation:

a || b and a line intersecting them is their transversal.

$\therefore m\angle 1=m\angle 5\\(corresponding \:\angle 's) \\\\\therefore 60 - 2x = 70 - 4x\\\\\therefore 4x - 2x = 70 - 60\\\\\therefore 2x = 10\\\\\therefore x =\frac{10}{2} \\\\\huge \orange {\boxed {\therefore x = 5}}$

4 0

3 years ago

6. Look at this graph: Is this relation a function? Yes or no

zmey [24]

Both are not functions because functions cannot have repeating x values

3 0

3 years ago

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Annabella wants to make the most economical decision so she chose the 3-year car loan so that after the loan is paid off to be a

Novay_Z [31]

Answer:

Annabella will save $4950.11 after 2 years.

Step-by-step explanation:

<h3>Given</h3>

Periodic payment P = $200,
Period t = 2 years,
Number of compounds, monthly n = 12,
Interest rate, r = 3.2% = 0.032.

Future value of saving, F

<h3>Solution</h3>

Use periodic compound formula:

$F=P\cfrac{(1+r/n)^{nt}-1}{r/n}$

Substitute the values and calculate:

$F=200\cfrac{(1+0.032/12)^{12*2}-1}{0.032/12} =4950.12$ rounded

6 0

1 year ago

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In a Science class students made rockets out of empty 2-liter bottles. When launched, Karen's rocket reached a height of 12 and

velikii [3]

13 9/10

This is just a math equation. Just add 12 1/2 to 1 2/5 and remember that the bottoms of fractions have to be the same and if you change the bottoms, you have to change the top just as much :)

8 0

3 years ago

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A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. How much time does it take for the r

Bogdan [553]

Check the picture below.

so it hits the ground when y = 0, thus

$\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{16}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{5}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}$

$\bf h(t)=-16t^2+16t+5\implies \stackrel{h(t)}{0}=-16t^2+16t+5
\\\\\\
16t^2-16t-5=0\implies (4t+1)(4t-5)=0\\\\
-------------------------------\\\\
4t+1=0\implies 4t=-1\implies t=-\cfrac{1}{4}\\\\
-------------------------------\\\\
4t-5=0\implies 4t=5\implies t=\cfrac{5}{4}\implies \boxed{t=1\frac{1}{4}}$

since "t" is seconds it took, it can't be a negative amount.

5 0

3 years ago