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3 years ago

14.976 divided by 6 with remainder

Mathematics

2 answers:

True [87]3 years ago

8 0

0 no remainder !! Ndnehensbebe

PIT_PIT [208]3 years ago

4 0

Answer:

Step-by-step explanation:

it's divided evenly with no remainder

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Solve for p... -5(p + 3/5) = -4

Alla [95]

Step-by-step explanation:

-5(p + 3/5 ) = -4

-5p - 3/5 *5 = -4

-5p - 3 = - 4

-5p = -4 +3

-5p = -1

therefore p = 1/ 5

7 0

3 years ago

Find the interest rate if £6400 has a final value of £8334 in 3 years. Give your answer to 1 d.p

Mila [183]

Answer:

Step-by-step explanation:

6400(1+i)³=8334

(1+i)³=1.3021875

∛(1+i)³=∛(1.3021875)

1+i= 1.092

i= .092

I guess if you were to round to 1 decimal point it'd be .1

4 0

3 years ago

Please need help!!! Find the x

Tomtit [17]

Answer:

5.7 units

Step-by-step explanation:

By geometric mean property:

$x = \sqrt{4 \times 8} \\ \\ x = \sqrt{32} \\ \\ x = 5.65685425 \\ \\ x \approx \: 5.7 \: units$

6 0

3 years ago

bongo had a balance of $345.28 in his checking account. During the week amounts: $65.08, $24.50, and $118.95. He then made a dep

vichka [17]

Answer: 192.75

Step-by-step explanation:

I am answering your question assuming that the three amounts were checks that were written out during the week.

Beginning balance = 345.28

Subtract the total amount of the checks (65.08 + 24.50 + 118.95 = 208.53)

345.28 - 208.53 = 136.75

Next, add the amount of the deposit. 136.75 + 56.00 = 192.75

8 0

3 years ago

The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^

Reika [66]

Answer:

(i) The value of m when t = 30 is 13.2

(ii) The value of t when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18

Step-by-step explanation:

(i) The m value when t = 30 is:

$m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2$

Then, the value of m when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

$m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24$

Now, the value of t is:

$ln(\frac{m_{0}/2}{24}) = -0.02t$

$t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7$

Hence, the value of t when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

$\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48* (e^{-0.02*50}) = -0.18$

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!

3 0

3 years ago