Answer:
46.57
Step-by-step explanation:
Given that:
h(t) = 37t - 4.9t²
When the ball reaches the ground, then the height is zero;
So, we equate h(t) to zero and solve for t
37t - 4.9t² = 0
t = 0, 7.55
Let the Initial time be a = t = 0
The time the ball reaches the ground be b = 7.55
So, the average height can now be calculated as:
Average height =
=
=
=
= 46.57091665
≅ 46.57 to (2 decimal places)
Answer:
A ≈ 269.81 cm²
Step-by-step explanation:
This shape is a hexagon (it has 6 sides) so let's use the formula for the area of a hexagon.
A =
Where s is the length of the sides
Substitute:
A =
A =
Solve:
A =
A =
Multiply the numerator:
A =
A ≈
(The numerator reflects a rounded number, but the actual calculations are exact)
Divide the fraction:
A ≈
A ≈ 2.6(100)
Multiply:
A ≈ 2.6(100)
A ≈ 269.81 cm²
Therefore, the area is approximately 269.82 cubic centimeters.