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il63 [147K]
3 years ago
13

A soup can has a diameter of 6.6cm. The label on the can is 8.8cm high. There is a 1cm overlap on the label. What is the area of

the label.
Mathematics
1 answer:
DanielleElmas [232]3 years ago
7 0
Calculate the circumference and then add the 1 cm overlap:

C = pi*(6.6 cm) + 1 cm = 21.7 cm.

Next, mult this C by the height, 8.8 cm:  Total area is 21.7 cm times 8.8 cm, 
or    191.3 cm^3 (answer)
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sdas [7]

Answer:

a

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b

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c

  n =   253

Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

                             n=    2300

   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
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DochEvi [55]

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Step-by-step explanation:

(2x^2-3x+5)(x^2+4x+1)\\(2x^2-12x+5)

3 0
3 years ago
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Rudik [331]

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Step-by-step explanation:

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So 3^n of the equation would be:
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Compare the 2 equations:
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The difference between the 2 equations is: 1, 3, 9 which itself is a geometric sequence so the nth term of this new equation is: 3^{n-1}.

Combine these 2 equations together and you get:

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