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3 years ago

Problem 3 Find the value of x.

Mathematics

2 answers:

Deffense [45]3 years ago

4 0

value of x should be 3.2 units

Answered by Gauthmath must click thanks and mark brainliest

svetoff [14.1K]3 years ago

3 0

3.2 units in your answer

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TIME REMAINING

Leya [2.2K]

Answer:

w=-7/2z

Step-by-step explanation:

to solve for w you firstly have to group the like terms

5w-3w=2z-9z

2w=-7z

then you have to divide both sides by 2 inorder to remain with w on one side.

2w/2=-7/2

w=-7/2

I hope this helps

3 0

3 years ago

Read 2 more answers

what is the volume of a cone with a diameter of 30 feet and height of 60 feet? use 3.14 for pi. enter your answer in the box

Marizza181 [45]

The volume of a cone with a diameter of 30 feet and a height of 60 feet is 14130.

<h3>What is the volume of a cone?</h3>

The volume of the cone is given by;

$\rm Volume \ of \ cone=\dfrac{1}{3}\pi r^2h\\\\Where;\ r = radius \ and \ h = height$

The volume of a cone with a diameter of 30 feet and a height of 60 feet.

The radius of the cone is;

$\rm Radius =\dfrac{Diameter}{2}\\\\Radius=\dfrac{30}{2}\\\\Radius=15$

Substitute all the values in the formula

$\rm Volume \ of \ cone=\dfrac{1}{3}\pi r^2h\\\\ Volume \ of \ cone=\dfrac{1}{3}\times 3.14 \times 15^2 \times 60\\\\Volume \ of \ cone=14130$

Hence, the volume of a cone with a diameter of 30 feet and height of 60 feet is 14130.

Learn more about the volume of cone here;

brainly.com/question/3013784

#SPJ2

5 0

2 years ago

Read 2 more answers

The length of a rectangle is twice its width.<br> The perimeter of the rectangle is 126 feet.

seraphim [82]

Answer: Length = 42ft Width = 21ft

Step-by-step explanation:

Let "w" be width

W = 21ft

w x 2 = L

L = 42ft

Perimeter:

42+42+21+21

=126

8 0

3 years ago

Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C

Lesechka [4]

Answer:

Solution : $-\frac{3}{4}-\frac{3}{4}i$

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]$

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

$\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}$