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xeze [42]
3 years ago
8

Problem 3 Find the value of x.​

Mathematics
2 answers:
Deffense [45]3 years ago
4 0

value of x should be 3.2 units

Answered by Gauthmath must click thanks and mark brainliest

svetoff [14.1K]3 years ago
3 0
3.2 units in your answer
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A box with a square base is wider than it is tall. In order to send the box through the U.S. mail, the width of the box and the
dlinn [17]

Answer:

Maximum Volume = 29,659.5 cubic inches

Step-by-step explanation:

We can write the perimeter as 2*(x+h) and this is equal to 117

So

2(x+h) = 117\\x+h=58.5\\h=58.5-x

The volume is  x^2(h)

Plugging the expression for h, we have:

V=x^2 h\\V=x^2(58.5-x)\\V=58.5x^2-x^3

The max volume can be found when this differentiated is equal to 0, or dV/dx=0

V=58.5x^2-x^3\\\frac{dV}{dx}=117x-3x^2=0\\3x(39-x)=0\\x=0,39

x can't be 0, so we take x = 39

and thus h=58.5-x = 58.5-39=19.5

Max Volume = x^2h=(39)^2 (19.5)=29,659.5

5 0
4 years ago
Find the measure of angle 2 if the measure of angle 8 is 40<br> degrees.
Vinvika [58]

Answer:

what is the shape?

Step-by-step explanation:

like is a square triangle or what ? show us a picture

8 0
3 years ago
Pleaseee helppppppppppppppppppp
quester [9]

To find Angle A we use cosine

cos ∅ = adjacent / hypotenuse

From the question

The adjacent is 17

The hypotenuse is 38

So we have

cos A = 17/38

A = cos-¹ 17/38

A = 63.4

<h3>A = 63° to the nearest degree</h3>

To find Angle C we use sine

sin ∅ = opposite / hypotenuse

From the question

The opposite is 17

The hypotenuse is 38

So we have

sin C = 17/38

C = sin-¹ 17/38

C = 26.57

<h3>C = 27° to the nearest degree</h3>

Hope this helps you

7 0
3 years ago
What is the correct answer!
AlexFokin [52]

Answer:

The answer is B.

Step-by-step explanation:

Please let me know if you want an explanation for why this is the answer (comment on this). A lot of people don't actually read the explanations, so I wouldn't want to waste my time. However, if you would like it I would be more than happy to type one out for you. Thanks!

6 0
3 years ago
Determine the zeros of r=2sin5theta
vazorg [7]

Answer:

\theta=\frac{n\pi}{5}

Step-by-step explanation:

You have the following function:

r=2sin5\theta          (1)

In order to find the zeros of the function you equal to zero the equation (1), and then you solve for θ:

2sin5\theta=0\\\\sin5\theta=0\\\\5\theta=sin^{-1}(0)=n\pi;\ \ \ \ n=0,1,2,3,..\\\\\theta=\frac{n\pi}{5}

Then, there are infinite zeros for the function of the equation (1), because n has infinite positive integers values.

6 0
3 years ago
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