Celeste and Dora both offer guitar lessons. Celeste charges an initial fee of $5.00, and an hourly rate of $7.25. Dora has an in
2 answers:
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Answer:
denominators are zero for x=1
there is no solution
Step-by-step explanation:
We suspect your equation is supposed to be ...
10/(5x -5) +1/5 = 2/(x -1) . . . . . parentheses are required on denominators
The denominators will be zero for x=1.
This version of the equation has no solution. It simplifies to ...
2/(x-1) + 1/5 = 2/(x -1)
1/5 = 0 . . . . . subtract 2/(x-1) from both sides
There is no value of x that will make this equation true.
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<em>Alternative interpretation</em>
The way your equation is written, it must be interpreted according to the order of operations to be ...
(10/5)x -5 +1/5 = (2/x) -1 . . . . x=0 makes the denominator zero
2x -3.8 = 2/x
2x^2 -3.8x = 2 . . . . multiply by x
2(x^2 -1.9x +.95^2) = 2 +2(0.95^2)
(x -0.95)^2 = 1.9025
x = 0.95 ± √1.9025 ≈ {-0.4293, 2.3293}
Answer:
The number of bacteria at initial = 187
Step-by-step explanation:
Given that the population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t.
Integrating both side we get
㏑ N = k t + C ------- (1)
Now given that after 3 hours it is observed that 500 bacteria are present and after 10 hours 5000 bacteria are present.
⇒ ㏑ 500 = 3 k + C -------- (2)
⇒ ㏑ 5000 = 10 k + C ------ (3)
⇒ ㏑ 5000 - ㏑ 500 = 7 k
⇒ ㏑ = 7 k
⇒ ㏑ 10 = 7 k
⇒ k = 0.329
Put this value of k in equation (2),
⇒ ㏑ 500 = 3 × 0.329 + C
⇒ C = 5.23
Put this value of C in equation 1 we get,
⇒ ㏑ N = k t + 5.23
Initially when t = 0 , then
⇒ ㏑ N = 5.23
⇒ N = 187
Thus the number of bacteria at initial = 187