$y=190*e^{-a*t}\\\\Calculate\ a:\\\\t=33,y=95(mg)\\\\190*e^{-a*33}=95\\\\e^{-a*33}=0.5\\\\-a*33=ln(0.5)\\\\a=\dfrac{ln(\dfrac{1}{2}) }{-33} \\\\a=0,02100... \approx{0.021}\\\\If\ t=51\ h, y=190*e^{-0.02100*51}=65.09167...\approx{65.1}$

6 0

3 years ago

The graph displays the total cost when buying gas by the gallon. Which statement best describes the relationship between cost an

xeze [42]

D the less gas you buy, the less it costs

7 0

3 years ago

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Why does a logarithmic equation sometimes have an extraneous solution?

jonny [76]

The main reason behind this is using properties of logarithm .

when solving

log_2(x+2)+log_2(x-3)=3

There you use multiplication property and make addition to multiplication then you get extraneous solution because in plenty of cases they occur

(-2)²=(2)²

But

-2≠2

Same happens in case of logarithm

6 0

2 years ago

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N aquarium tank holds

Lilit [14]

1 gal = 3.8 liters....so 65 gallons = 65 * 3.8 = 247 liters

4 0

3 years ago