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Dvinal [7]
3 years ago
10

If you have a saturated solution at equilibrium, what changes could you make to increase the solubility of the compound?.

Chemistry
1 answer:
Elza [17]3 years ago
3 0

1. A colloid may look homogeneous from the outside, but is a heterogeneous mixture.

2. Diameter of the particles of colloids ranges between 1-100 nm.

3. Tyndall effect is observed in colloids if a light beam passes through it. Solution with large solute particles, which are intermediate in diameter between those in correct solutions and those in suspensions are defined as colloids.

Explanation

Characteristics of colloids:

The size of particles in a colloid is greater than those in a correct solution but lesser than those in a suspension. The diameter of a colloid particle lies between 1 nm and 100 nm.

A colloid is a heterogeneous mixture of dispersed phase and dispersed medium. For example, butter is a colloid in which tiny fat droplets stay dispersed in a liquid to form an emulsion.

Special techniques like centrifugation apply to separate colloid particles. The filtration process is useless in separating the constituents of a colloid.

The particles of a colloid are so large that they can scatter a beam of light passing through it. This is known as Tyndall effect.

Colloid particles do not aggregate at the bottom of the vessel if the solution is left undisturbed.

1. A colloid may look homogeneous from the outside, but a heterogeneous mixture.

2. Diameter of the particles of colloids ranges between 1-100 nm.

3. Tyndall effect is observed in colloids if a light beam passes through

A solution with large solute particles, which are intermediate in diameter between those in correct solutions and those in suspensions, are defined as colloids.

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why do solids keep their shape and volume why do liquids keep only volume and why do gases not keep either shape or volume
kodGreya [7K]
Solids always have definite shape and definite volume because their particles are packed together. Liquids have a definite volume but not definite shape, because their particles still kinda tight but able to move around, and gases don’t have a definite shape nor volume, because their particles are crazy and go everywhere
6 0
3 years ago
Which of these are the correct base pairs of DNA?
Oduvanchick [21]
B) Cytosine and guanine.

The pairs are A/T and C/G.
6 0
3 years ago
Read 2 more answers
Write electron configurations for Gallium, Ga (Z=31), and show the total valence electrons
ivann1987 [24]

<u>Answer:</u> The electronic configuration of gallium is written below and number of valence electrons is 3.

<u>Explanation:</u>

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

Valence electrons are defined as the electrons present in the outermost shell of an atom.

We are given:

An element Gallium having atomic number as 31.

Number of electrons = 31

Electronic configuration of Gallium is: (Z=31):1s^22s^22p^63s^23p^64s^23d^{10}4p^1

This element has 3 electrons in its outermost shell. So, the number of valence electrons is 3

Hence, the electronic configuration of gallium is written below and number of valence electrons is 3.

3 0
4 years ago
What is the mass present in a 10.0L container of oxygen at a pressure of 105kPa and 20 degrees Celsius
omeli [17]

1.31 × 10⁴ grams.

<h3>Explanation</h3>

Assume that oxygen acts like an ideal gas. In other words, assume that the oxygen here satisfies the ideal gas law:

P \cdot V = n \cdot R\cdot T,

where

  • P the pressure on the gas, \bf P = 10^{5}\;\textbf{kPa}=10^{8}\;\textbf{Pa};
  • V the volume of the gas, V = 10.0 \;\text{L} = 10.0\times 10^{-3}\;\text{m}^{3}=10^{-2}\;\text{m}^{3};
  • n the number of moles of the gas, which needs to be found;
  • T the absolute temperature of the gas, T=20\;\textdegree{}\text{C} = (20 + 273.15)\;\text{K} = 293.15\;\text{K}.
  • R the ideal gas constant, R = 8.314 if P, V, and T are in their corresponding SI units: Pa, m³, and K.

Apply the ideal gas law to find n:

n = \dfrac{P\cdot V}{R\cdot T} = \dfrac{{\bf 10^{8}\;\textbf{Pa}}\times 10^{-2}\;\text{m}^{3}}{8.314 \;\text{Pa}\cdot\text{m}^{3}\cdot\text{K}^{-1}\cdot\text{mol}^{-1}\times 293.15\;\text{K}} = 410.3\;\text{mol}.

In other words, there are 410.3 moles of O₂ molecules in that container.

There are two oxygen atoms in each O₂ molecules. The mass of mole of O₂ molecules will be {\bf 2}\times 16.00 = 32.00\;\text{g}. The mass of 410.3 moles of O₂ will be:

410.3 \times 32.00 = 1.31\times10^{4}\;\text{g}.

What would be the mass of oxygen in the container if the pressure is approximately the same as STP at 10^{5}\;\textbf{Pa} or  10^{2}\;\text{kPa} instead?

6 0
4 years ago
What is the concentration (molarity) of NaOH if 29.39 mL of the solution is neutralized by 31.46 mL of 2.67 M HCL
Dennis_Churaev [7]

Answer:

0.083

Explanation:

Explanation:

We're asked to find the molar concentration (molarity) of the HCl solution, given some titration measurements.

Let's first write the chemical equation for this neutralization reaction:

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Since we're given the molarity and volume of the NaOH solution used, we can calculate the moles be using the molarity equation:

mol solute=(molarity)(L soln)

=(0.1molL)(0.0332L)=0.00332 mol NaOH

Since all the coefficients in the chemical equation are 1, the relative number of moles of HCl used is also 0.00332 mol.

Finally, let's use the molarity equation again to find the molarity of the HCl solution (given the volume of NaOH soln is 40 mL, which must be in liters when using molarity equations):

molarity=mol soluteL soln

=0.00332lmol HCl0.040lL=0.083M

6 0
4 years ago
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