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Verdich [7]
3 years ago
7

Compare the way that frogs breathe when they are tadpoles with the way frogs breathe when they are adults.

Chemistry
2 answers:
Ad libitum [116K]3 years ago
7 0

Answer:Frogs breathe through gills underwater to get oxygen and when frogs are adults they breathe through their lungs to get oxygen.

Explanation:

andreev551 [17]3 years ago
6 0
When frogs are tadpoles they, they breathe through their gills, as frogs they have mucus glands in their skin which helps them absorb oxygen from the air, or they can also breathe through their lungs
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5 0
2 years ago
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How many joules are needed to warm 65.6 grams of water from 14ºC to 22.5ºC?
Ahat [919]

Answer:

2334.1136 Joules

Explanation:

Q= 65.6 g (4.186)(8.5)

If it's suppose to be in kilograms, the answer will be 2.3341136 Joules.

7 0
3 years ago
How many grams of CO are produced when 41.0 g of C reacts?
CaHeK987 [17]

Answer:

95.7 g CO to the nearest tenth.

Explanation:

2C + O2 ---> 2CO

Using relative atomic masses:

24 g C produces  2*12 + 2*16 g CO.

So 41 g produces  ( (2*12 + 2*16) * 41  ) / 24

= 95.7 g CO,

7 0
3 years ago
A mixture with H2 and He exerts a total pressure of 0.48 atm. If there is 1.0 g of H2 and 1.0 g of He in the mixture, what is th
lara [203]

Answer is: the partial pressure of the helium gas is 0.158 atm.

p(mixture) = 0.48 atm; total pressure.

m(H₂) = 1.0 g; mass of hydrogen gas.

n(H₂) = m(H₂) ÷ M(H₂).

n(H₂) = 1.0 g ÷ 2 g/mol.

n(H₂) = 0.5 mol; amount of hydrogen.

m(He) = 1.0 g; mass of helium.

n(He) = 1 g ÷ 4 g/mol.

n(He) = 0.25 mol; amount of helium.

χ(H₂) = 0.5 mol ÷ 0.75 mol.

χ(H₂) = 0.67; mole fraction of hydrogen.

χ(He) = 0.25 mol ÷ 0.75 mol.

χ(He) = 0.33; mole fraction of helium.

p(He) = 0.33 · 0.48 atm.

p(He) = 0.158 atm; the partial pressure of the helium gas.

8 0
3 years ago
Calculate the mass percent (m/m) of a solution prepared by dissolving 45.09 g of NaCl in 174.9 g of H2O.
inysia [295]

Answer:

20.3 %  NaCl

Explanation:

Given data:

Mass of solute = 45.09 g

Mass of solvent = 174.9 g

Mass percent of solution = ?

Solution:

Mass of solution = 45.09 g + 174.9 g

Mass of solution = 220 g

The solute in 220 g is 45.09 g

220 g = 2.22 × 45.09

In 100 g solution amount of solute:

45.09 g/2.22 = 20.3 g

Thus m/m% = 20.3 %  NaCl

5 0
3 years ago
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