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Verdich [7]
3 years ago
7

Compare the way that frogs breathe when they are tadpoles with the way frogs breathe when they are adults.

Chemistry
2 answers:
Ad libitum [116K]3 years ago
7 0

Answer:Frogs breathe through gills underwater to get oxygen and when frogs are adults they breathe through their lungs to get oxygen.

Explanation:

andreev551 [17]3 years ago
6 0
When frogs are tadpoles they, they breathe through their gills, as frogs they have mucus glands in their skin which helps them absorb oxygen from the air, or they can also breathe through their lungs
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lutik1710 [3]

Answer:

A GALAXY WIITH I YHINK MANY

Explanation:

3 0
3 years ago
Use Q = mcAT
mr Goodwill [35]

Answer:

1).....for the specific heat capacity(c) of water is 4200kg/J°C..

....guven mass(m)=320g(0.32kg)

...change in temperature(ΔT) =35°C

from the formula

Q=mcΔT

Q=0.32Kg x 4200kg/J°C x 35°C

Q=47,040Joules

5 0
3 years ago
Which of the following combinations of coefficients correctly balances this chemical equation: 2H2S (g) + __O2 (g) __CO2 (g) + 2
frez [133]
In chemistry for an chemical equation to be complete it has to be balanced using appropriate coefficients and state symbols such similar atoms are equal in both sides of the equation. The reaction between hydrogen sulphide and oxygen gas yields sulphur iv oxide and water as indicated by equation.
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therefore the correct answer is 2,3,2,2
7 0
3 years ago
A sample of 25.0 mL of 0.120 M Ca(OH)2(aq) is titrated with 0.150 M HCl(aq). What volume of HCl(aq) is needed to completely neut
stiv31 [10]

Answer:

V_{HCl}=48.0 mL

Explanation:

Hello!

In this case, since the reaction between calcium hydroxide and hydrochloric acid shows a 2:1 mole ratio between them:

2HCl+Ca(OH)_2\rightarrow CaCl_2+2H_2O

We need to use the following mole ratio:

2n_{Ca(OH)_2}=n_{HCl}

That can be written in volumes and concentrations:

2M_{Ca(OH)_2}V_{Ca(OH)_2}=M_{HCl}V_{HCl}

Thus, we solve for the volume of HCl as it is the unknown:

V_{HCl}=\frac{2M_{Ca(OH)_2}V_{Ca(OH)_2}}{M_{HCl}}

Therefore, we plug in to obtain:

V_{HCl}=\frac{2*0.120M*25.0mL}{0.150M} \\\\V_{HCl}=48.0 mL

Best regards!

3 0
3 years ago
A sample of argon gas at stp occupies 56.2 liters. determine the number of moles of argon and the mass in the sample. for the ab
andreev551 [17]
We can use the ideal gas law equation to find the number of moles;
PV = nRT
where P - pressure
V - volume - 56.2 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature 
standard temperature is 273 K
and standard pressure - 101 325 Pa
we can rearrange the equation to find the number of moles 
n =  \frac{PV}{RT}
substituting the values in the equation 
n =  \frac{101325Pa*56.2 x 10⁻³ m³}{8.314 Jmol⁻¹K⁻¹*273K}
n = 2.51 mol 
molar mass of Ar - 40 g/mol
mass of Ar in the sample - 2.51 mol x 40 g/mol = 100.4 g
7 0
4 years ago
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