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madreJ [45]
3 years ago
6

Help plzzzzzzzzzzzz! I need help with this

Business
2 answers:
Novosadov [1.4K]3 years ago
8 0
I believe your answer is b
V125BC [204]3 years ago
7 0
Simple answer is B.
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Abey​ Kuruvilla, of Parkside​ Plumbing, uses 1,220 of a certain spare part that costs ​$26 for each​ order, with an annual holdi
lina2011 [118]

Answer:

Answer:

Total cost = Total ordering cost + Total holding cost

Total cost = DCo/Q    + QH/2

Where D = Annual demand, Co = Ordering cost per order and H = holding cost per item per annum.

For 25 Order Size

Total cost = 1,220 x $26/25  + 25 x $25/2

Total cost = $1,268.80 + $312.50 = $1,581.30

For 40 Order Size

Total cost = 1,220 x $26/40  + 40 x $25/2

Total cost = $793 + $500 = $1,293.00

For 50 Order Size

Total cost = 1,220 x $26/50 + 50 x $25/2

Total cost = $634.40 + $625 = $1,259.40

For 60 Order Size

Total cost = 1,220 x $26/60  + 60 x $25/2

Total cost = $528.67 + $750 = $1,278.67

For 100 Order Size

Total cost = 1,220 x $26/100  +  100 x $25/2

Total cost = $317.20 + $1,250 = $1,567.20

b. The economic order quantity is 50 units because it reduces the total cost to $1,259.40

Explanation:

In this case, we need to determine the total costs based on different order sizes. Thus, economic order quantity is the order size that minimises the total cost.

4 0
3 years ago
Why do we practice making associations with simple and mundane problems and resources? Select all that apply.
Artyom0805 [142]

Answer:

E.  They are problems and resources that most people have experience with or can relate to.

Explanation:

  • Such problems and resources are most commonly found in day to day lives. People can easily relate to them as they are simple and common in the workplace.
  • They are associated with the resources of particular problems. This making them a subject of practice it becomes easy to use them for teaching and other purposes. Such as enlightenment and giving advice.
4 0
2 years ago
You want to buy a house that costs $140,000. You have $14,000 for a down payment, but your credit is such that mortgage companie
rodikova [14]

Answer:

Kindly check explanation

Explanation:

Given the following :

Cost of house = $140,000

Down payment = $14000

Take back mortgage = 126000 = PV

Rate (r) = 5%

Yearly payment one can afford = 22000

a. If the loan was amortized over 3 years, how large would each annual payment be? Could you afford those payments?

Number of period = 3

Using the relation:

PMT = r(PV) / 1 - (1 + r)^-n

PMT = 0.05(126000) / 1 - 1.05^-3

PMT = 6300 / (1-0.8638375)

PMT = 46,268.23

He won't be able to afford it, as the monthly payment is larger than the affordable amount of $22000

b. If the loan was amortized over 30 years, what would each payment be? Could you afford those payments?

PMT = r(PV) / 1 - (1 + r)^-n

PMT = 0.05(126000) / 1 - 1.05^-30

PMT = 6300 / (1-0.2313774)

PMT = 8196.48

He would be able to afford it, as the monthly payment is lower than the affordable amount of $22000

c. To satisfy the seller, the 30-year mortgage loan would be written as a balloon note, which means that at the end of the third year, you would have to make the regular payment plus the remaining balance on the loan. What would the loan balance be at the end of Year 3, and what would the balloon payment be?

Present value of remaining balance after the 3rd year:

Present Value (PV) = PMT[(1 - (1 + r)^-n) / r]

Where

PMT = periodic payment = 8196.48

r = Interest rate = 5% = 0.05

n = number of periods = 30 - 3 = 27

PV = 8196.48[(1 - (1 + 0.05)^-27) / 0.05]

PV = 8196.48[(1 - (1. 05)^-27) / 0.05]

PV = 8196.48[0.7321516 / 0.05]

PV = 120,021.32

Balloon payment :

120,021.32 + 8196.48 = 128,217.80

4 0
2 years ago
) The typical family on the Planet Econ consumes 10 pizzas, 7 pairs of jeans, and 20 gallons of milk. In 2016, pizzas cost $10 e
Firdavs [7]

Answer: um... Imma say 6 i guess i don't really know

Explanation:

8 0
2 years ago
Whispering Winds Corporation owns equipment that cost $64,800 when purchased on April 1, 2013. Depreciation has been recorded at
Aleonysh [2.5K]

Answer:

(a) update depreciation for 2018

Debit ; Depreciation $10,800

Credit Accumulated Depreciation  $10,800

(b) record the sale

Debit : Cash $12,960

Debit : Accumulated Depreciation $62,100

Credit : Profit and Loss $10,260

Credit : Equipment at Cost $64,800

Explanation:

(a) update depreciation for 2018

Recognize deprecation

(b) record the sale

Recognize proceeds from sale and profit or loss from sale

7 0
3 years ago
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