<u>Answer:</u>
<h2>A = 15 u²</h2>
<u>Explanation:</u>
according to the coordinates the triangles is right at the pair (2, -3)
the area of the triangle = height × base × 1/2
the <u>height</u> is the line passing through the pairs (-1, 6) and (2, -3)
h² = (2-(-1))²+(-3-6)²
h² = 3² + (-9)²
h² = 9 + 81
h² = 90
h = √90
the <u>base</u> is the line passing through the pairs (5, -2) and (2, -3)
b² = (2-5)²+(-3-(-2))²
b² = 3² + (-3+2)²
b² = 9 + 1
b² = 10
b = √10
A = h×b×1/2
A = √90×√10×1/2
A = √900×1/2
A = 30×1/2
A = 15 u²
4/5 is the answer to reduce to the lowest of 16/20
Answer as a fraction: 17/6
Answer in decimal form: 2.8333 (approximate)
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Work Shown:
Let's use the two black points to determine the equation of the red f(x) line.
Use the slope formula to get...
m = slope
m = (y2-y1)/(x2-x1)
m = (4-0.5)/(2-(-1))
m = (4-0.5)/(2+1)
m = 3.5/3
m = 35/30
m = (5*7)/(5*6)
m = 7/6
Now use the point slope form
y - y1 = m(x - x1)
y - 0.5 = (7/6)(x - (-1))
y - 0.5 = (7/6)(x + 1)
y - 0.5 = (7/6)x + 7/6
y = (7/6)x + 7/6 + 0.5
y = (7/6)x + 7/6 + 1/2
y = (7/6)x + 7/6 + 3/6
y = (7/6)x + 10/6
y = (7/6)x + 5/3
So,
f(x) = (7/6)x + 5/3
We'll use this later.
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We ultimately want to compute f(g(0))
Let's find g(0) first.
g(0) = 1 since the point (0,1) is on the g(x) graph
We then go from f(g(0)) to f(1). We replace g(0) with 1 since they are the same value.
We now use the f(x) function we computed earlier
f(x) = (7/6)x + 5/3
f(1) = (7/6)(1) + 5/3
f(1) = 7/6 + 5/3
f(1) = 7/6 + 10/6
f(1) = 17/6
f(1) = 2.8333 (approximate)
This ultimately means,
f(g(0)) = 17/6 as a fraction
f(g(0)) = 2.8333 as a decimal approximation
