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Andrej [43]
3 years ago
9

Help me plsx i really need it

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0
D=3t/d hope this helps
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Of 80 people attending a dance 28 dance with their hands touching the floor. If four people at the dance are selected at random,
tensa zangetsu [6.8K]

Answer: The probability is 0.013

Step-by-step explanation:

Out of 80 people, 28 of them dance with the hands touching the ground.

Then, the probability of selecting at random someone that dances with the hands touching the floor is equal to the number of persons that dance in that way, divided by the total number of persons.

For the first selection, this is p1 = 28/80

now, the probability in the second selection will be 27/79, because we have selected 1 out of the 28 (and also 1 out of the 80)

for the third and the fourth we have:

p3 = 26/78

p4 = 25/77

Then the probability of the fourth events is equal to the product of the four probabilities:

P = (28/80)*(27/79)/(26/78)/(25/77) = 0.013

3 0
3 years ago
Read 2 more answers
Which of the following numbers is not divisible by 11 A)40579 B)109857 C)162383 D)110011​
Vika [28.1K]
The answer is C

162,383/11= 14762.09091
8 0
3 years ago
Read 2 more answers
Please help me out. Will make as brainiest!
frutty [35]

Answer:

Quadratic function

Step-by-step explanation:

6 0
3 years ago
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6
USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

The coordinates are given as:

\mathbf{(x,y) = (-60,0)\ (60,0)}

The center of the hyperbola  is  

\mathbf{(h,k) = (0,0)}

The distance from the center to the focal points is given as:

\mathbf{c = 60}

Square both sides

\mathbf{c^2 = 3600}

The distance from the receiver to the transmitters  is given as:

\mathbf{2a = 100}

Divide both sides by 2

\mathbf{a = 50}

Square both sides

\mathbf{a^2 = 2500}

We have:

\mathbf{b^2 = c^2 - a^2}

This gives

\mathbf{b^2 = 3600 - 2500}

\mathbf{b^2 = 1100}  

The equation of an hyperbola is:

\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}

So, we have:

\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}

\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Hence, the equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Read more about hyperbolas at:

brainly.com/question/15697124

7 0
3 years ago
Read 2 more answers
What is the area if a sector with radius 10" and measure of arc equal to 45°?
guajiro [1.7K]
We know that
[area of a circle]=pi*r²
r=10 in
[area of a circle]=pi*10²-----> 100*pi in²

if  360° (full circle) has an area of------------------> 100*pi in²
 45°-------------------------------> X
X=45*100*pi/360-----> x=12.5*pi in²

the answer is
the option B) 12.5*pi in²
3 0
3 years ago
Read 2 more answers
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