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stira [4]
3 years ago
5

Help help help help help

Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

Step-by-step explanation:

1. no

2. yes

3. yes

4. yes

5. 5.2

6. 4.5

7. 2.5

8. 16

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Find an equation for the line that passes through the points (-2,-6) and (6,-4)
JulsSmile [24]
Slope of line
m= (y2-y1)/(x2-x1)
=(-4--6)/(6--2)
=2/8
=1/4

Line in two point form
(y-y1)=m(x-x1)
y--2=(1/4)(x-6)
y+2=(1/4)(x-6)
simplify
4(y+2)=x-6 =>
x-4y-14=0
Alternatively, use the slope intercept form:
y--2=(1/4)(x-6) =>
y=(1/4)x - 3/2-2 =>
y=(1/4)x -7/2

6 0
3 years ago
GIVING BRAINLIEST AND CREDIT ;)))))) DONT LEAVE ME HANGING
melamori03 [73]

Answer:

Type the equations given into desmos and it will give you the answer


8 0
3 years ago
Plz don’t answer saying I can’t see or I don’t understand
Norma-Jean [14]
The answers should be

1. -12d-2
2. 56a+32b
3. 6a-12b+18
4. 8g+8h-16
5 0
2 years ago
Find z such that 4.8% of the standard normal curve lies to the left of z. (Round your answer to two decimal places)
lukranit [14]

Answer:

The correct answer will be "-1.66".

Step-by-step explanation:

Let z₀ be,

P(z

                =0.048

⇒ \Phi (z_0)=0.048

Now,

⇒ \Phi (-1.6646)=0.048

   z_0=-1.6646

       \simeq  -1.66

Thus the above is the right answer.

3 0
3 years ago
A car is at a distance s, in miles from its starting point in t hours, given by s(t)=10t^2. Find s(2) and s(5). Find s(5)-s(2).
weeeeeb [17]

Answer:

Average Velocity= 70 miles per hour

Step-by-step explanation:

Distance= s

Time = t

s(t)=10t^2

Putting the values

s(2) = 10 (2)^2= 10&4

s= 40

s(5) = 10 (5)^2 = 10*25

S(5)= 250

The average velocity is defined as the rate of change of speed in unit time.

So

Speed= distance/time

Velocity = Speed in a definite direction

Average Velocity= Displacement/ Time

Average Velocity= Change in distance/ Change in time

s(5) - s(2)/ t(5)- t(2)

= 250-40/5-2= 210/3= 70 miles per hour

4 0
3 years ago
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