Solve for m <br>-2(m +5) +14 =-6

How many cookies will Tanya have if she bakes 12 more batches?y=70+18(x)

Mumz [18]

Y=70+18(x)
y=70+18(12)
y=70+216
y=286

7 0

3 years ago

A lumber company is making doors that are 2058.02058.0 millimeters tall. If the doors are too long they must be trimmed, and if

nataly862011 [7]

Answer:

$t=\frac{2044-2058}{\frac{17}{\sqrt{15}}}=-3.190$

$df=n-1=15-1=14$

$p_v =P(t_{(14)}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly lower than 2058 mm at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=2044$ represent the sample mean

$s=17$ represent the sample standard deviation

$n=15$ sample size

$\mu_o =2058$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 2058 mm, the system of hypothesis are :

Null hypothesis: $\mu \geq 2058$

Alternative hypothesis: $\mu < 2058$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2044-2058}{\frac{17}{\sqrt{15}}}=-3.190$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=15-1=14$

Since is a one-sided lower test the p value would be:

$p_v =P(t_{(14)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly lower than 2058 mm at 5% of signficance.

8 0

3 years ago

Adimas found the mean of her 11 math test scores for the first semester. x = StartFraction (76 + 87 + 65 + 88 + 67 + 84 + 77 + 8

Lilit [14]

Answer:

71.36 and 8.45

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?

VashaNatasha [74]