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Sonbull [250]
3 years ago
5

Find the volume of the solid The problem is in the picture!!!!!!!!!

Mathematics
1 answer:
Anna35 [415]3 years ago
3 0
The answer will be C. In the picture you will see 2144 which is the answer.

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Hi! Answer this please!
Rudiy27
The answer would be b
4 0
2 years ago
Read 2 more answers
I NEED HELP ASAP!!!!
dedylja [7]

Answer:

B) 8

Step-by-step explanation:

Triangles MNC and RSC are similar because all 3 angles are the same, so the the ratio between each side should be the same.

If NC=12 and SC=6 then triangle MNC is scaled up by 2 from triangle RSC. This means each side of MNC is 2 times bigger than on RSC. So, sense RS=4, we can multiply that by 2 to get MN=8.

8 0
2 years ago
Pleaseee help will give brainliest!!A-(-3.75)=6.11
cricket20 [7]

Answer:

Step-by-step explanation:

A=6.11-3.75=2.36

5 0
3 years ago
HELP I NEED THIS NOW!!!!
borishaifa [10]

Answer:

<u>So, The area of trapezoid = 4.413 R²</u>

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and m∠NMK = 65° , OT = R

So, m∠MNP = 180° - 65° = 115° ⇒ supplementary interior angles.

<u>Join </u>ON ⇒ ΔOSN is a right triangle at S.

And NP, NM are tangents to the circle

So, ON bisects the angle ∠MNP = ∠MNS

∠ONS = (∠MNS)/2 = 115/2 = 57.5°

So, tan (∠ONS) = OS/NS = R/(NS)

NS = R/tan (∠ONS)=R/(tan 57.5°) ≈ 0.637 R

<u>∴ NP = 2 * NS = 1.274 R</u>

<u>Construct: a line parallel to ST from N to line MK</u>

let the intersection point be Q  ⇒ NQ = 2R

So, Δ NQM is a right triangle at Q

tan (∠NMQ) = tan 65 = NQ/MQ

MQ = NQ/(tan 65)=2R/tan 65 ≈ 0.932 R

∴ MK = 2 MT = 2 (MQ + QT) ⇒ QT = NS

         = 2 (MQ + NS ) = 2( 0.932 R + 0.637 R) = 2 * 1.569 R

<u>∴ MK = 3.139 R</u>

<u></u>

Now, area of trapezoid = height × (sum of parallel sides/ 2)

Area = ST * (NP + MK)/2

        = 2R * (1.274 R + 3.139 R) / 2

        = 2R * 4.413 R /2

       = 4.413 R²

So, The area of trapezoid = 4.413 R²

5 0
2 years ago
Helppp helping my sister
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