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3 years ago

PLEASE HELP IM BEGGING PLEASEEEE SEE ATTACHED DOCUMENT

Mathematics

1 answer:

ANTONII [103]3 years ago

3 0

Answer:

Step-by-step explanation:

3x-1 = 4x+13

-1=x+13

12=x

3(12)-1

36-1

Answer: 35

Second 5.

I'm not completely sure what this is referring to (please tell me if there is another part for this because there isn't any numbers such as <1 shown on the picture.)

90+40+x=180

130+x=180

50=x

Answer: 50

x+71=90

x=19

Answer: 19

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What is the correct value of z?<br> A. Z=12<br> B. Z=13<br> C. Z=10<br> D. Z=11

inna [77]

<h3>Answer: A) z = 12</h3>

==========================================

Work Shown:

RS = RT

2z-15 = 9

2z = 9+15

2z = 24

z = 24/2

z = 12

The reason why RS is equal to RT in the first equation is because we have an isosceles triangle. Recall that any isosceles triangle has exactly two sides the same length, and the opposite base angles are congruent to one another. The congruent angles are indicated with the single arcs.

In short: the base angles S and T are congruent, so the opposite sides RS and RT are the same length. This leads to RS = RT.

3 0

2 years ago

What is the real answer !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Troyanec [42]

Real answer for what??

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3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

3 years ago

You throw a ball at a height of 5 feet above the ground. The height h (in feet)

Serjik [45]

Answer:

Step-by-step explanation:

4 0

3 years ago

Convert 39°C to degrees Fahrenheit.

posledela

Given a temperature C in celsius, you can convert it to Fahrenheit by using the formula

$F=32 + \dfrac{9C}{5}$