Given:
AB is the diameter of a circle.
m∠CAB = 26°
To find:
The measure of m∠CBA.
Solution:
Angle formed in the diameter of a circle is always 90°.
⇒ m∠ACB = 90°
In triangle ACB,
Sum of the angles in the triangle = 180°
m∠CAB + m∠ACB + m∠CBA = 180°
26° + 90° + m∠CBA = 180°
116° + m∠CBA = 180°
Subtract 116° from both sides.
116° + m∠CBA - 116° = 180° - 116°
m∠CBA = 64°
The measure of m∠CBA is 64°.
Answer:
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Step-by-step explanation:
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Answer:
first one x = 26
second one x = 11.12
Step-by-step explanation:
a^2 + b^2 = c^2
24^2 + 10^2 = c^2
676 = c^2
26 = c
a^2 = c^2 - b^2
a^2 = 12^2 - 4.5^2
a^2 = 123.75
a = 11.12
Answer:
{(1-2g) + 4h] x 5 =
Step-by-step explanation:
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