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2 years ago

Simplifly -3(x+4)+5x

Mathematics

2 answers:

Alisiya [41]2 years ago

6 0

Answer:

2x-12

Step-by-step explanation:

Nataliya [291]2 years ago

5 0

Answer:

-3x+-12+5x

3x+5x-12

8x-12

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Which expression is equivalent to 4z+2z

Pepsi [2]

Answer:6z

Step-by-step explanation:

4z+2z=6z

4 0

3 years ago

Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

The formula f= 1.8 + 32 is used to convert temputure from degrees celsius ºC to degrees

Svetach [21]

Answer:

The Formula F=1.8C+32 gives the temperature in degrees Celsius (C). There is one temperature for which a number of degrees Fahrenheit is equal to the number of degrees Celsius.

Step-by-step explanation:

20ºC = 68ºF i think this is equation.;-;

3 0

2 years ago

2.6 in.<br> 3 in. +<br> 6 in.

ivanzaharov [21]

Answer:

11.6in

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third

ivanzaharov [21]

Answer:

The three consecutive integers are 12, 13, 14.

Step-by-step explanation:

Encode the question in an equation. We are given two facts: (1) the three integers are consecutive, and (2) they relate to each other through a sum.

Pick any of the integers (first, second, or third) and call it n. Then write the two others correspondingly in terms of n. I pick the middle one as n, so the three consecutive integers are (n-1), n, (n+1). That's (1). As for (2), here is the fact:

$(n-1)+2n = 80-3(n+1)$

Lo and behold, one equation with one unknown! Easy to solve for n to give us the middle integer, n:

$(n-1)+2n = 80-3(n+1)\\3n-1= 80-3n -3\\6n =78\\n = 13$

The three consecutive integers are 12, 13, 14.

3 0

3 years ago