So 4 inches diameter result the radius is 4/2 = 2 inches
area of base = pir^2 = 3,14*2^2 = 3,14*4 = 12,56 inches squared
volume = area of base *height
V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed
hope this will help you
C is what you do when credit cards are involved.
Answer:
A. 29i
Step-by-step explanation:
Step 1: Plug in given variables
(2 - 5i)(2 + 5i)i
Step 2: Difference of squares (expand)
(4 - 25i²)i
Step 3: Imaginary numbers rules
(4 - 25(-1))i
Step 4: Combine like terms
(4 + 25)i
(29)i
Your final answer will be 29i
First, change it into general form(y=my+b).
3y=6x-1+10
3y=6x+9
y=2x+3
So, the slope is 2, and the y-intercept is 3
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
