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andreyandreev [35.5K]
2 years ago
12

Choose the graph below that represents the following system of inequalities: (1 point)

Mathematics
1 answer:
weqwewe [10]2 years ago
8 0

Answer:

How much

Step-by-step explanation:

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Peter purchased 14 new baseball cards for his collection. This increased the size of his collection by 35%. How many baseball ca
Vlad [161]

Answer:

<em>Peter now has 54 baseball cards</em>

Step-by-step explanation:

<u>Percentages</u>

Assume Peter had x baseball cards in his collection. The 35% of his initial collection is

35 * x / 100= 0.35x

We know that those 14 new baseball cards represent a 35% of his previous collection, therefore we can set a simple equation

0.35x=14

When we solve for x, we'll know how many baseball cards Peter had before

x=14 / 0.35 = 40

Peter had 40 cards, he added 14 new baseball cards, so he now has 40+14=54

Peter now has 54 baseball cards

8 0
3 years ago
5(15-7y/3)+2y=-4<br>solve for y and plz show steps​
Burka [1]

Answer:

75 - 35y / 3 + 2y = -4

( 75 - 35y + 6y ) / 3 = -4 [ Taking LCM ]

( 75 - 29y ) / 3 = -4

75 - 29y = -12

29y = 75+12

29y = 87

y = 3

hope that helps ✌

5 0
3 years ago
Read 2 more answers
What number can be written as 40+5
Salsk061 [2.6K]
45 that is the answer
5 0
3 years ago
Read 2 more answers
Please help due asap
Nadusha1986 [10]
Answer:5
Explanation:Pythagorean Theorem
4 0
2 years ago
If $-2 &lt; x \le 3,$ then find all possible values of $5x + 1.$ Give your answer in interval notation.
kotegsom [21]

Answer: (-9, 16]

This is the interval from -9 to 16. Exclude -9 but include 16.

=====================================================

Work Shown:

The idea is to multiply all sides by 5, then add 1 to all sides

-2 < x \le 3

5(-2) < 5x \le 5(3)

-10 < 5x \le 15

-10+1 < 5x+1 \le 15+1

-9 < 5x+1 \le 16

This converts to the interval notation  (-9, 16]

note: a curved parenthesis means "do not include this value in the solution set"; while a square bracket has us include the value. So we exclude -9 and include 16.

3 0
3 years ago
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