Given:
The system of equations is


To find:
The missing value for which the given system of equations have infinitely many solutions.
Solution:
Let the missing value be k.
We have,


Taking all the terms on the left side, the given equations can be rewritten as


The system of equations
and
have infinitely many solutions if

We have,


Now,



On cross multiplication, we get


Therefore, the missing value is -10.
Twice a number increased by 5= 2x+5
5 decreased by twice a number= 5-2x
twice the difference of a number and 5= 2(x-5)
Twice the sum of a number and 5= 2(x+5)
Five subtracted from twice a number= 2x-5
Twice a number, less 5= 2x-5
<h3>
Answer:</h3>
- left picture (bottom expression): -cot(x)
- right picture (top expression): tan(x)
<h3>
Step-by-step explanation:</h3>
A graphing calculator can show you a graph of each expression, which you can compare to the offered choices.
_____
You can make use of the relations ...
... sin(a)+sin(b) = 2sin((a+b)/2)cos((a-b)/2)
... cos(a)+cos(b) = 2cos((a+b)/2)cos((a-b)/2)
... cos(a)-cos(b) = -2sin((a+b)/2)sin((a-b)/2)
Then you have ...

and ...

The area of 3x5 face is used 4 times rather then twice
S=94in ^2
2a.) 8.8 x 4 = 35.2g
2b.) 35.2 x 30 = 1056g or 1.056kg