The given congruency of the sides 
and 
and 
and 
as well
as the congruency of the common side 
gives.
ΔBEL ≅ ΔLOB by SSS congruency postulate
<h3>Which values correctly completes the table?</h3>
The completed two column proof is presented as follows;
Statement 
Reasons
1. 
1. Given
2. 
≅ 
2.
3. 
3. <u>Reflexive property of congruency</u>
4. ΔBEL ≅ ΔLOB 4. <u>SSS congruency postulate</u>
Side-Side-Side, SSS, congruency postulate states that if three sides of
one triangle are congruent to three sides of another triangle, the two
triangles are congruent.
Learn more about different congruency postulates here:
brainly.com/question/1495556
The circle is closed and the graph is shaded to the right also there’s a negative on the x, you have to get rid of it first by dividing by -1 and then you switch direction of the less than or equal to greater than or equal because you divided by negative
Step 1: Simplify both sides of the equation.
Step 2: Subtract 6x from both sides.
- 65x²+390x+585−6x=6x−6x
- 65x²+384x+585=0
For this equation: a=65, b=384, c=585
Step 3: Use quadratic formula with a=65, b=384, c=585
- x=−b±√b2−4ac/2a
- x=−(384)±√(384)2−4(65)(585)/
- 2(65)
- x=−384±√−4644/130
Therefore, There are no real solutions.
The correct answer is line q
Answer:
A
Step-by-step explanation:
