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andreyandreev [35.5K]
3 years ago
12

Choose the graph below that represents the following system of inequalities: (1 point)

Mathematics
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

How much

Step-by-step explanation:

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There are 4 white tokens and 6 blue tokens in a bag. Once a token is selected, it is not replaced. Find the probability of selec
Mkey [24]

Answer: 2/15

Step-by-step explanation: To find this compound probability, first note that there is no replacement.

The probability of drawing the first white token is 4/10 or 2/5.

The probability of drawing the second token is 3/9 or 1/3 because one white token has already been taken away. Now, multiply 2/5 by 1/3 to get the answer, which is 2/15

5 0
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Which numbers are rational?
ELEN [110]

Answer:

a,c,d,e,f,g is correct answer

5 0
3 years ago
Explain how you would use algebra tiles to solve x - 3 = 7
Andrew [12]

Answer:

Start by laying out 7 tiles, and then adding 3. Whatever that number of tiles is equals x.

x = 10

10 - 3 = 7

7 0
3 years ago
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A skateboard travels 55 feet in 4 seconds. Is the skateboard going faster, slower, or the same speed as the scooter?
Assoli18 [71]

Answer:

Slower.

Step-by-step explanation:

I belive it is slower because the scooter was 30 feet per 2 seconds. 30+30+60 feet, 2+2= 4 seconds= 60 feet and 4 seconds which makes the 55 feet per 4 seconds slower.

4 0
4 years ago
2% of the population suffers from the terrible disease conditionitis. The test for conditionitis comes back positive 98% of the
vlabodo [156]

Answer:

8% probability that he or she actually has the disease

Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?

This means that:

Event A: Test comes back positive.

Event B: Having the disease.

Test coming back positive:

2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that P(A|B) = 0.98

For the 100-2 = 98% who do not have the disease, the test comes back positive 100-77 = 23% of the time.

Then

P(A) = 0.02*0.98 + 0.98*0.23 = 0.245

Finally:

P(B|A) = \frac{0.02*0.98}{0.245} = 0.08

8% probability that he or she actually has the disease

6 0
4 years ago
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