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Reptile [31]
3 years ago
7

Solve for x and round to the nearest tenth

Mathematics
1 answer:
ANEK [815]3 years ago
6 0

Answer:

x = 6.0

Step-by-step explanation:

Given:

Line AB is the hypotenuse

50.1 degrees is an angle

90 degrees is a right angle

Line CB is x and is opposite to the 50.1 degree angle

Line AC is 5 and is adjacent to the 50.1 degree angle

We know we have angles of 50.1 degrees and 90 degrees

We could find the third angle by doing 180 = 50.1 + 90 + a; a = 39.9 degrees

Sin(angle) = Opp/Hyp, Cosine(angle) = Adj/Hyp, Tan(angle) = Opp/Adj

We know the adjacent length, degree of angle, and are looking for the opposite side; therefore, we can use tan(angle) = opp/adj

tan(50.1) = x/5

x = 5.9979

or

tan(angle) = opp/adj

tan(39.9) = 5/x

x = 5.9979

Round to the nearest tenth:

x = 6.0

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Answer:

3x,3x+8,x^{2} ,x^{2}+6,4^{x} ,4^{x}+3,

Step-by-step explanation:

We have to arrange the functions given in ascending order which have eventually the least value and eventually the greatest value.

So, we get the following table representing the values of the functions for different values of x.

x                    :     5                   10                   15

y_{1} =3x+8    :     23               38                    53

y_{2} =4^{x} +3   :    1027         1048579          1073741827

y_{3} =x^{2} +6   :     31                106                   231

y_{4} =3x        :     15                30                     45

y_{5} =4^{x}        :     1024       1048576        1073741824

y_{6} =x^{2}        :      25              100                    225

As, can be seen from the table that the ascending order of the functions is given by y_{4},y_{1},y_{6},y_{3},y_{5},y_{2},.

Hence, the order is 3x,3x+8,x^{2} ,x^{2}+6,4^{x} ,4^{x}+3,.

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3 years ago
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