Is 16 an option because if it is then... it's right?
Answer:
Step-by-step explanation:
You can answer these "what is the value of the digit ..." questions by setting all other digits in the number to zero.
A) The value of the 7 in 10,709 is 700.
B) The value of the 7 in 17,009 is 7,000.
C) 7000 is ten times as great as 700. (7000/700 = 10)
_____
The point of a "place value" number system is that the value of the number depends on its place in the number. Each such number system has a "base." For a decimal number, the base is ten.
The value of a digit in any place value number system increases by a factor equal to the base when that digit is moved 1 place to the left.
Here, the 7 in the second number is 1 place to the left of the 7 in the first number, so its value is increased by a factor of 10.
Well, It's going to be 8/12 and then reduced it will be 4/6 or 0.667
<h2>
Answer:</h2>
The speed of the commercial jet is
while the speed of the private airplane is ![330mi/h](https://tex.z-dn.net/?f=330mi%2Fh)
<h2>
Step-by-step explanation:</h2>
Let's name the commercial jet as cj and private airplane as pa, so we know the following:
<u>It takes the commercial jet 1.1 hours for the flight, so:</u>
![t_{cj}=1.1h](https://tex.z-dn.net/?f=t_%7Bcj%7D%3D1.1h)
<u>It takes the private airplane 1.8 hours for the flight, so:</u>
![t_{pa}=1.8h](https://tex.z-dn.net/?f=t_%7Bpa%7D%3D1.8h)
<u>The speed of the commercial jet is 210 miles per hour faster than the speed of the private airplane:</u>
Let's name the speed of the commercial jet as
and the speed of the private airplane as
, then:
![v_{cj}=v_{pa}+210](https://tex.z-dn.net/?f=v_%7Bcj%7D%3Dv_%7Bpa%7D%2B210)
From physics we know that:
![v=\frac{d}{t} \\ \\ Where: \\ \\ v: \ speed \\ \\ d: \ distance \\ \\ t: \ time](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D%20%5C%5C%20%5C%5C%20Where%3A%20%5C%5C%20%5C%5C%20v%3A%20%5C%20speed%20%5C%5C%20%5C%5C%20d%3A%20%5C%20distance%20%5C%5C%20%5C%5C%20t%3A%20%5C%20time)
Since the distance from Denver to phoenix is unique, then:
![d_{cj}=d_{pa}=d](https://tex.z-dn.net/?f=d_%7Bcj%7D%3Dd_%7Bpa%7D%3Dd)
Thus, from the equation
and given the relationship
we have:
![v_{cj}=v_{pa}+210 \\ \\ \frac{d}{t_{cj}}=\frac{d}{t_{pa}}+210 \\ \\ \\ Plug \ in \ t_{cj}=1.1 \ and \ t_{pa}=1.8 \ then: \\ \\ \frac{d}{1.1}=\frac{d}{1.8}+210 \\ \\ Isolating \ d: \\ \\ d(\frac{1}{1.1}-\frac{1}{1.8})=210 \\ \\ \frac{35}{99}d=210 \\ \\ d=\frac{99\times 210}{35} \\ \\ d=594miles](https://tex.z-dn.net/?f=v_%7Bcj%7D%3Dv_%7Bpa%7D%2B210%20%5C%5C%20%5C%5C%20%5Cfrac%7Bd%7D%7Bt_%7Bcj%7D%7D%3D%5Cfrac%7Bd%7D%7Bt_%7Bpa%7D%7D%2B210%20%5C%5C%20%5C%5C%20%5C%5C%20Plug%20%5C%20in%20%5C%20t_%7Bcj%7D%3D1.1%20%5C%20and%20%5C%20t_%7Bpa%7D%3D1.8%20%5C%20then%3A%20%5C%5C%20%5C%5C%20%5Cfrac%7Bd%7D%7B1.1%7D%3D%5Cfrac%7Bd%7D%7B1.8%7D%2B210%20%5C%5C%20%5C%5C%20Isolating%20%5C%20d%3A%20%5C%5C%20%5C%5C%20d%28%5Cfrac%7B1%7D%7B1.1%7D-%5Cfrac%7B1%7D%7B1.8%7D%29%3D210%20%5C%5C%20%5C%5C%20%5Cfrac%7B35%7D%7B99%7Dd%3D210%20%5C%5C%20%5C%5C%20d%3D%5Cfrac%7B99%5Ctimes%20210%7D%7B35%7D%20%5C%5C%20%5C%5C%20d%3D594miles)
Finally, the speeds are:
![\bullet \ v_{cj}=\frac{d}{t_{cj}} \\ \\ v_{cj}=\frac{594}{1.1} \therefore \boxed{v_{cj}=540mi/h} \\ \\ \\ \bullet \ v_{pa}=\frac{d}{t_{pa}} \\ \\ v_{pa}=\frac{594}{1.8} \therefore \boxed{v_{pa}=330mi/h}](https://tex.z-dn.net/?f=%5Cbullet%20%5C%20v_%7Bcj%7D%3D%5Cfrac%7Bd%7D%7Bt_%7Bcj%7D%7D%20%5C%5C%20%5C%5C%20v_%7Bcj%7D%3D%5Cfrac%7B594%7D%7B1.1%7D%20%5Ctherefore%20%5Cboxed%7Bv_%7Bcj%7D%3D540mi%2Fh%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cbullet%20%5C%20v_%7Bpa%7D%3D%5Cfrac%7Bd%7D%7Bt_%7Bpa%7D%7D%20%5C%5C%20%5C%5C%20v_%7Bpa%7D%3D%5Cfrac%7B594%7D%7B1.8%7D%20%5Ctherefore%20%5Cboxed%7Bv_%7Bpa%7D%3D330mi%2Fh%7D)