Answer:
linkage with approximately 33 map units between the two gene loci
Explanation:
If two genes are not linked, number of recombinants and parental offspring will be equal. Here it is clearly visible that recombinants are less than parental offspring hence the genes are linked. Given, the offspring are in following numbers:
AaBb = 106 = Parental
aabb = 94 = Parental
Aabb = 48 = Recombinant
aaBb = 52 = Recombinant
Recombination frequency = (Number of recombinants/ Total progeny) * 100 = (100/300) * 100 = 33.33 %
1% recombination frequency= 1 map unit of distance between the two gene loci. So here the distance between the two gene loci is approximately 33 map units.
Hence, these results are consistent with linkage with approximately 33 map units between the two gene loci
When parallel light rays exit a concave lens the light rays diverge. Option A. This is further explained below.
<h3>What is ray divergence?</h3>
Generally, ray divergence is simply defined as when light rays begin at a point and diverge,
In conclusion, when light rays begin at a point and spread, it is called ray divergence.
Read more about Light
brainly.com/question/25770676
Answer:
glycolysis
Explanation:
In the process of glycolysis only 2 molecules of ATP are produced. Maximum energy is released, when the reduced coenzymes produced in the process of Krebs cycle are oxidised in the process of oxidative phosphorylation in electron transport chain.
