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SpyIntel [72]
3 years ago
6

there are 2 1\2 bus loads of students standing in a parking lot. The students are getting ready to go on a field trip. 2\5 of th

e students on reach bus are girls. How many busses would it take to carry only girls?
Mathematics
2 answers:
Zinaida [17]3 years ago
5 0
It will take only one full  bus!
Archy [21]3 years ago
3 0
It would take only one full bus to carry only girls.
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Step-by-step explanation:

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2 years ago
Juan always saves the same amount from his weekly allowance. The table shows how much he has saved at different times.
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You're correct, it is B. If you plug in 3 (weeks) in for "x" and 19 (amount saved) for "y" you will get 0=0, which is a solution.
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Tems11 [23]

Answer:

As Per Provided Information

We have to use π = 3.14

Diameter of baseball is 3 inch

So, Radius of Baseball will be

  • Radius = Diameter/2

Radius = 3/2 inch

Radius = 1.5 inch

we have been asked to determine the surface area of given baseball .

<u>Using </u><u>Formulae </u>

<u>\boxed {\bf  \: Surface \:  Area_{(Baseball)} \:  = 4 \pi {r}^{2} }</u>

substituting the value and let's solve it

\longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = 4 \times 3.14 \times  {1.5}^{2}  \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 4 \times 3.14 \times 2.25 \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 12.56 \times 2.25 \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 28.26 \:  {inch}^{2}

<u>Therefore</u><u>,</u>

  • <u>Surface</u><u> </u><u>Area </u><u>of</u><u> </u><u>baseball</u><u> </u><u>is </u><u>2</u><u>8</u><u>.</u><u>2</u><u>6</u><u> </u><u> </u><u>sq.</u><u> </u><u>inch</u><u> </u><u>.</u>

So, your answer is 28.26 sq.in

4 0
2 years ago
Help me please this is due tommorow morning
nataly862011 [7]

Answer:

E: (2, -1)

F: (3, -1)

G: (3, -2)

H: (2, -2)

Step-by-step explanation:

Reflect all coordinates over an x-axis

Because you are reflection 180 degrees over the x axis, the y-axis is going to stay the same (because you are not moving the square left or right. When reflecting over axis always add the same amount you took away from the other side, if that makes any sense.

7 0
3 years ago
The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi
kondaur [170]

Answer:

0.9

0.3012

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230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0
3 years ago
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