The probability of Aya being offered a coupon on at least one of the six days she visits the website is 100% minus the probability that she is not offered a coupon on any of the six days, which is described by a binomial probability with zero successes in six trials with a probability of succes p = 0.15.

$P = 1 - (\frac{6!}{(6-0)!0!}* p^0*(1-p)^{6-0})\\P = 1 - (1* 1*(1-0.15)^{6})\\P=0.6229=62.29\%$

The probability that Aya will be offered a coupon on at least one of the days she visits the website is 62.29%.

8 0

3 years ago

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Helppppppp please:( and thank you

Shtirlitz [24]

Answer:

180-140=50 180-90-50= 40 m=40

3 0

3 years ago

I need help with this math question

ICE Princess25 [194]

Answer:

B. 5

Step-by-step explanation:

Step 1: Rewrite the equation a bit

$\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}$

Step 2: Place a logarithm base 7 on both sides

$7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}\\log_77^\frac{3}{4}^-^\frac{x}{8}=log_77^\frac{1}{8}\\(\frac{3}{4}-\frac{x}{8})log_77=\frac{1}{8}log_77\\(\frac{3}{4}-\frac{x}{8})1=\frac{1}{8}1\\\frac{3}{4}-\frac{x}{8}=\frac{1}{8}$

Step 3: Solve for x

$\frac{3}{4}-\frac{x}{8}=\frac{1}{8}\\\frac{6}{8}-\frac{x}{8}=\frac{1}{8}\\-\frac{x}{8}=-\frac{5}{8}\\\frac{x}{8}=\frac{5}{8}\\x=5$

Neat exponent question :)

7 0

2 years ago