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2 years ago

6

PLSSSSS HELP!!

1 answer:

GenaCL600 [577]2 years ago

5 0

Answer:

p = 10.50 + b b = 10.50 + p b = 10.50p p = 10.50b

Step-by-step explanation:

The values on the x axis are 0, 2, 4, 6, 8, 10. The values on the y axis are 0, 21, 42, 63, 84, and 105. Points are shown on ordered pairs 0, 0 and ..

The graph below shows the price of different numbers of mats at a store: A graph is shown. The values on the x axis are 0, 2, 4, 6, 8, 10. The values on the y axis are 0, 21, 42, 63, 84, and 105. Po - the ... 21, 42, 63, 84, and 105. Points are shown on ordered pairs 0, 0 and 2, 21 and 4, 42 and 6, 63 and 8, 84.

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PLEASE HELP ASAP !!

ololo11 [35]

Answer:

MK

Step-by-step explanation:

ML is the short side of right triangle MLK. MJ is the hypotenuse of right triangle MKJ. This gives you a clue that the ratios of interest are the short side to the hypotenuse. All these right triangles are similar, so ...

ML/MK = MK/MJ . . . . . ratio of short side to hypotenuse is the same

ML·MJ = MK² . . . . . . . cross multiply

MK = √(ML·MJ) . . . . . the geometric mean of ML and MJ is MK

7 0

3 years ago

An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft 3 . Find the d

denpristay [2]

Answer:

The dimensions of the box that minimize the materials used is $6\times 3\times 2\ ft$

Step-by-step explanation:

Given : An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft³.

To find : The dimensions of the box that minimize the materials used ?

Solution :

An open top box is to be built with a rectangular base whose length is twice its width.

Here, width = w

Length = 2w

Height = h

The volume of the box V=36 ft³

i.e. $w\times 2w\times h=36$

$h=\frac{18}{w^2}$

The equation form when top is open,

$f(w)=2w^2+2wh+2(2w)h$

Substitute the value of h,

$f(w)=2w^2+2w(\frac{18}{w^2})+2(2w)(\frac{18}{w^2})$

$f(w)=2w^2+\frac{36}{w}+\frac{72}{w}$

$f(w)=2w^2+\frac{108}{w}$

Derivate w.r.t 'w',

$f'(w)=4w-\frac{108}{w^2}$

For critical point put it to zero,

$4w-\frac{108}{w^2}=0$

$4w=\frac{108}{w^2}$

$w^3=27$

$w^3=3^3$

$w=3$

Derivate the function again w.r.t 'w',

$f''(w)=4+\frac{216}{w^3}$

For w=3, $f''(3)=4+\frac{216}{3^3}=12 >0$

So, it is minimum at w=3.

Now, the dimensions of the box is

Width = 3 ft.

Length = 2(3)= 6 ft

Height = $\frac{18}{3^2}=2\ ft$

Therefore, the dimensions of the box that minimize the materials used is $6\times 3\times 2\ ft$

4 0

3 years ago

Write the expression in simplest form.<br><br> (-11/2x + 3) -2 (-11/4x - 5/2) = ?

mina [271]

(- $\frac{11}{2}$ x + 3) - 2(- $\frac{11}{4}$ x - $\frac{5}{2}$ ) = ?

in simplest form-

(-5 $\frac{1}{2}$ x + 3) -2( 2 $\frac{3}{4}$ x -2 $\frac{1}{2}$ )

6 0

2 years ago

In-s [12.5K]

Hii

The answer us - 5/4

Sorry if incorrect

8 0

2 years ago

Read 2 more answers

-3x + 5 = -4x - 10 solution??? ill give brainlist

mrs_skeptik [129]

Answer:

x=-10

Step-by-step explanation:

hope this helps, sorry if i get wrong

DO NOT PICK ANSWER IT IS WRONG.

3 0

2 years ago

Read 2 more answers