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Sedbober [7]
3 years ago
11

HURRY HELP

Mathematics
2 answers:
fgiga [73]3 years ago
8 0

Answer:

A is equal to the fraction

Gnom [1K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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When 3x² - 2x + 1 is subtracted from 2x² +7x + 5, the result will be?​
Karolina [17]

Answer:

-x²+9x+4

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
Read 2 more answers
What decimal represents the fraction 1/4
Sedaia [141]

Answer:

0.25

Step-by-step explanation:

1/4 is equal to 1.00 split into 4 equal parts. 0.25*4 = 1.00 , meaning that each 1/4 is equal to 0.25

3 0
2 years ago
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I need help please you will get branliest
AnnZ [28]

Answer:C= 9

Step-by-step explanation:

c−7=1×2

c−7=2

c=2+7

c=9

3 0
2 years ago
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Solve.
Pavlova-9 [17]

Answer:

  (2, -3)

Step-by-step explanation:

Apparently, the equations are supposed to be ...

  • 4x +y = 5
  • 3x +y = 3

The solution for x can be found by subtracting the second equation from the first:

  (4x +y) -(3x +y) = (5) -(3)

  x = 2 . . . . . . . matches the second answer choice

Y can be found from either equation:

  y = 5 - 4x . . . . . subtract 4x from the first equation

  y = 5 -4(2) = -3

The solution is (x, y) = (2, -3).

7 0
3 years ago
Apples cost $0.75 per pound and bananas cost $1.05 per pound
LuckyWell [14K]

Answer:

<em>The baker bought 8 apples and 4 bananas</em>

Step-by-step explanation:

<u>System of Equations</u>

Let's call:

a = pounds of apples

b = pounds of bananas

The baker bought a total of 12 pounds of apples and bananas, thus:

a + b = 12      [1]

Apple cost $0.75 per pound and each pound of bananas cost $1.05 per pound. Thus the total cost is 0.75a + 1.05b. We know he spent a total of $10.20, thus

0.75a + 1.05b = 10.20     [2]

Solving [1] for a:

a = 12 - b       [3]

Substituting in [2]:

0.75(12 - b) + 1.05b = 10.20

Operating

9 - 0.75b + 1.05b = 10.20

Simplifying:

0.30b = 10.20 - 9 = 1.20

Dividing by 0.30:

b = 1.20/0.30

b = 4

From [3]:

a = 12 - 4 = 8

a = 8

The baker bought 8 apples and 4 bananas

8 0
3 years ago
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