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erma4kov [3.2K]
3 years ago
11

Please help need anser

Mathematics
2 answers:
denis23 [38]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Likurg_2 [28]3 years ago
8 0

Answer:

(C)

Step-by-step explanation:

i took a test and got is sorry bad at speeling :(

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S19for 11 + 19 + 27 + 35 +...
MrRissso [65]

8 is the answer because it goes 11 and if you add 8 it becomes 19 add 8 it becomes 27 add 8 35 add 8 43

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What are two decimals with thousandths that would give 0.2 when rounded to the nearest tenth and 0.20 when rounded to the neares
ale4655 [162]
To answer your questions, 3.216 and 7.203.
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3 years ago
A Ferris Wheel 22.0m in diameter rotates once every 12.5s. What is the ratio of a persons apperenet weight to her real weight (a
AnnZ [28]
  <span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed: 
a = omega^2*r 

omega and r in terms of given data: 
omega = 2*Pi/T 
r = d/2 

Thus: 
a = 2*Pi^2*d/T^2 

What forces cause this acceleration for the passenger, at either top or bottom? 

At top (acceleration is downward): 
Weight (m*g): downward 
Normal force (Ntop): upward 

Thus Newton's 2nd law reads: 
m*g - Ntop = m*a 

At top (acceleration is upward): 
Weight (m*g): downward 
Normal force (Nbottom): upward 

Thus Newton's 2nd law reads: 
Nbottom - m*g = m*a 

Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame: 
Ntop = m*(g - a) 
Nbottom = m*(g + a) 


Substitute a: 
Ntop = m*(g - 2*Pi^2*d/T^2) 
Nbottom = m*(g + 2*Pi^2*d/T^2) 

We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground): 
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g) 
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g) 

Simplify: 
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2) 
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2) 

Data: 
d:=22 m; T:=12.5 sec; g:=9.8 N/kg; 

Results: 
Ntop/(m*g) = 71.64%...she feels "light" 
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
7 0
3 years ago
Read 2 more answers
What is the relationship between 5,000 and 500,000
solong [7]
5000 is 1/100 of the value of 500,000
5 0
3 years ago
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Consider functions f and g defined by the graph and the table.<br><br> Please help me ASAP
Fed [463]

Answer:

Step-by-step explanation:

Given are two functions represented one by graph and another by table

We can check the given statement one by one

1) f(2)=18 : f(0) =15

Average rate of change = \frac{18-15}{2-0} =1.5

For g(x) avg rate of change

=\frac{g(2)-g(0)}{2-0} \\=4

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True

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3) True because y intercept is 10 for f while 8 for g

4) True because f(3) <g(3)

5) False both cannot be linear

3 0
2 years ago
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