Easy just use the method rise over run
Answer:
C
Step-by-step explanation:
m∠7=m∠3
3x-10=2x+5
x=15
m∠3=2(15)+5
=35
m∠1=m∠3 (vert. opp. ∠)
= 35
L=7+W
area=30=LW
so subsitute 7+W for length
30=(7+W)(W)
30=W²+7W
minus 30 both sides
0=W²+7W-30
factor
what 2 numbers multiply to get -30 and add to get 7
-3 and 10
0=(W-3)(W+10)
set to zero
0=W-3
3=W
0=W+10
-10=W
false, can't have a negative width
width=3in
L=7+W
L=7+3
L=10
the length is 10in
the width is 3in
Use the cosine law to find the length of side c:

![\begin{gathered} c^2=1^2+9^2-2(1)(9)\cos 60 \\ c^2=1+81-18\cos 60 \\ c^2=82-18\cos 60 \\ c^2=82-9 \\ c^2=73 \\ c=\sqrt[]{73} \\ c\approx8.54 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3D1%5E2%2B9%5E2-2%281%29%289%29%5Ccos%2060%20%5C%5C%20c%5E2%3D1%2B81-18%5Ccos%2060%20%5C%5C%20c%5E2%3D82-18%5Ccos%2060%20%5C%5C%20c%5E2%3D82-9%20%5C%5C%20c%5E2%3D73%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B73%7D%20%5C%5C%20c%5Capprox8.54%20%5Cend%7Bgathered%7D)
Use the cosine law to find the measure of angles A or B: