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Savatey [412]
3 years ago
13

7th grade math help me pleaseee

Mathematics
1 answer:
Andrew [12]3 years ago
5 0
(a) 3 x 3 x 3 x 3
(b) 4 x 4 x 4
(c) 5 x 5
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Which word describes their measures? linear congruent complementary supplementary
kkurt [141]
I would say congruent
8 0
2 years ago
Can someone help me on this im so confused
devlian [24]

Answer:

y

Step-by-step explanation:

A constant in an equation for example the equation 3x-7=5, the constant would be 7 and 5, the coefficient would be 3, the variable would be x and lastly, the subtraction sign would be the operator. So the answer would be y.

7 0
2 years ago
Complete the recursive formula of the arithmetic sequence -3, -1, 1, 3,...
Strike441 [17]

Given:

The given arithmetic sequence is:

-3,-1,1,3,...

To find:

The recursive formula of the given arithmetic sequence.

Solution:

We have,

-3,-1,1,3,...

Here, the first term is -3. So, b(1)=-3.

The common difference is:

d=-1-(-3)

d=-1+3

d=2

The recursive formula of an arithmetic sequence is:

b(n)=b(n-1)+d

Where, d is the common difference.

Putting d=2, we get

b(n)=b(n-1)+2

Therefore, the recursive formula of the given arithmetic sequence is b(n)=b(n-1)+2, where b(1)=-3.

8 0
3 years ago
The little Mexican restaurant sells only two kinds of beef burritos mucho beef sandwich Lucho beef last week the restaurant orde
Finger [1]

Answer:

Cost of a single Mucho beef burrito: \$5.5

Cost of a double Mucho beef burrito: \$6.5

Step-by-step explanation:

<h3> The exercise is: "The Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant sold 16 orders of the single Mucho variety and 22 orders of the double Mucho. If the restaurant sold $231 Worth of beef burritos last week and the single neutral kind cost $1 Less than the double Mucho, how much did each type of burrito cost?"</h3>

Let be "x" the the cost in dollars of a single Mucho beef burrito and "y" the cost in dollars of a double Mucho burrito.

Set a system of equations:

\left \{ {{16x+22y=231} \atop {x=y-1}} \right.

To solve this system you can apply the Substitution Method:

1. Substitute the second equation into the first equation and solve for "y":

16(y-1)+22y=231\\\\16y-16+22y=231\\\\38y=231+16\\\\y=\frac{247}{38}\\\\y=6.5

2. Substitute the value of "y" into the second equation and evaluate in order to find the value of "x":

x=6.5-1\\\\x=5.5

5 0
3 years ago
7. CHALLENGE: Use the digits 0 to 9 to make the equation true. You don't need to use all thedigits you can only use each digit o
labwork [276]

9514 1404 393

Answer:

  20 = 2 + (7 -4) × 6

Step-by-step explanation:

The Order of Operations requires the parentheses be evaluated first, then the multiplication performed. Finally, the addition is performed.

If each of the blanks is filled with a single digit, the result of the multiplication must be a composite number greater than 10. Those are 12, 14, 15, 16, 18, 20. For the expression shown above, we have chosen to make the product be 18. That means the first blank is filled with 2 and the remaining blanks must evaluate to one of the products 2×9 or 3×6.

We have chosen 6 for the last blank, so the two blanks in parentheses must have a difference of 3. The digits 2 and 6 cannot be used, leaving possible choices as (3-0), (4-1), (7-4), (8-5).

Our final expression is chosen to be ...

  20 = 2 +(7 -4)×6

3 0
3 years ago
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