All categories

2 years ago

What is the equation for a circle with the center, (0,0) and a radius of 4?

Mathematics

1 answer:

Leno4ka [110]2 years ago

6 0

Answer:

(X-x0)^2 +(y-y0)^2= r^2

R=4

R^2=16

(X-0)^2+(y-0)^2=16

You might be interested in

felix is a car mechanic. he can fix 2 motorcycles and 3 cars in 170 minutes. he can fix 1 motorcycle and 5 cars in 225 minutes.

vekshin1

Answer:

2x+3y=170.......1

1x+5y=225.......2

multiplying equation 2 by 2 and subtracting eq.1 &2

2x+3y-2x-10x=170-225

-7x=-55

x=55/7

55/7+5y=225

5y=225-55/7

y=1520/(7×5)=304/7

4 0

2 years ago

The height, h, in feet, of an object thrown upward from a height of 144 feet is a function of time, t, in seconds. The height ca

maxonik [38]

That should read:

h(t)=-16t^2+128t+144

h(3)=-16*9+128*3+144

h(3)=384

4 0

3 years ago

The ordered pairs are (-5,29), (3,-11) and (11,-51). What would be the slope-intercept form?

Free_Kalibri [48]

Answer:

$y = -5x + 4$

Step-by-step explanation:

Slope-intercept: $y = mx + b$

x y

-5 29

3 -11

11 -51

3 0

2 years ago

Geometry > 0.6 Area of sectors XZQ

Ratling [72]

Answer:

4π mi²

Step-by-step explanation:

s = (∅/360) * πr²

s = (135/360) * π(4²)

s = (135/360)(16) * π

s = 4π mi²

3 0

2 years ago

a village having a population of 4000, requires 150 litres of water per head per day. it has a tank measuring 20m x 15m x 6m. fo

allochka39001 [22]

The water will last for 3 days

Solution:

Given that, village having a population of 4000, requires 150 litres of water per head per day

Let us first find the volume of tank

The tank measuring 20m x 15m x 6m

Length = 20 m

Breadth = 15 m

Height = 6 m

$volume\ of\ tank = length \times breadth \times height$

$Volume\ of\ tank = 20 \times 15 \times 6 = 1800$

Thus volume of tank is 1800 cubic meter

From given,

Water required per person per day = 150 liters

Therefore, water required for 4000 people per day is:

$\rightarrow 4000 \times 150 = 600000 \text{ liters }$

Convert to meters

$600000 \text{ liters } = 600000 \times \frac{1}{1000}\ m^3\\\\600000 \text{ liters } = 600\ m^3$

How many days will the water of this tank last?

$\text{Number of days water will last } = \frac{\text{volume of tank}}{\text{total water required per day}}$

$\text{Number of days water will last } = \frac{1800}{600} = 3$

Thus the water will last for 3 days

5 0

2 years ago