What is the equation for a circle with the center, (0,0) and a radius of 4?

a store received 12 boxes of doughnuts. Each box contained 12 doughnuts. Which expression represents how many doughnuts there ar

Pachacha [2.7K]

Answer:

12x12=144 doughnuts

Step-by-step explanation:

3 0

3 years ago

A farmer wants to fence in a rectangular field that encloses 3600 square feet. One side of the field is along a river and does n

andriy [413]

Answer:

C(x) = $\$3.50(\frac{x^2+7200}{x})$

Step-by-step explanation:

Data provided in the question:

Area of the field = 3600 square feet

Fencing charges = $3.50 per foot

Let the side along the river be 'x' feet and the other side of the 'B'

now,

Area of rectangle = Bx = 3600 square feet

or

B = $\frac{3600}{x}$ feet

and total length to be fenced = x + 2B

therefore,

Total cost of fencing = Fencing charges × total length to be fenced

or

Total cost of fencing = $3.50 × ( x + 2B )

substituting the value of B from (1)

Total cost of fencing, C(x) = $\$3.50(x+2\times\frac{3600}{x})$

or

C(x) = $\$3.50(\frac{x^2+7200}{x})$

4 0

3 years ago

PARAMETRIC EQUATIONS HELP!!!

Alona [7]

Answer:

1. Option A

2. Option B

Step-by-step explanation:

I would like to elaborate on the answer to the second question, since the first answer is actually option a. Why? The question asks for a parametric equation, not set, so it would be choice a.

2. x=3t + 5 - isolate t

t=(x-5)/3 - substitute into the second equation

y = [(x-5)/3]^2 - 1

your solution is option b

4 0

3 years ago

Lee charges $3 for a basket and $2.50 for each pound of fruit picked at the orchard.

Sliva [168]

Answer:

Y=2.50x+3

Step-by-step explanation:

Because the $3 fee is not changing but the 2.50 is changing every pound that they get.

7 0

3 years ago

Read 2 more answers

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago