División de fracciones. 2/5÷10/7

Mathematics

1 answer:

xeze [42]3 years ago

8 0

jk,Answer:

Step-by-step explanation:

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En la final de un concurso escolar de

Sati [7]

Usando la distribución hipergeométrica, la probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es: 0.2 = 20%.

<h3>¿Qué es la fórmula de distribución hipergeométrica?</h3>

La fórmula es:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Los parámetros son:

x es el número de éxitos.

N es el tamaño de la población.

n es el tamaño de la muestra.

k es el número total de resultados deseados.

Los valores de los parámetros son:

N = 6, k = 3, n = 2.

La probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es P(X = 2), por eso:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,3) = \frac{C_{3,2}C_{3,0}}{C_{6,2}} = 0.2$

Puede-se aprender más a cerca de la distribución hipergeométrica en brainly.com/question/24826394

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4 0

2 years ago

Select the correct answer. A line each runs from point B through points A and C. First arc, centered at B, cuts line B A at J an

anastassius [24]

In order to make point D as the vertex in the construction as triangle ABC, the third arc should cross the second arc.

In Geometry, an arc can be defined as a trajectory that is generally formed when the distance from a given point has a fixed numerical value.

In order to make point D as the vertex in the construction as triangle ABC, you must ensure that the third arc crosses the second arc as illustrated in image attached below.

Read more on arc here: brainly.com/question/20594692

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