Answer:
the third one 10 cm, 9cm 9cm
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The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
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Answer:
y=2x-4
Step-by-step explanation:
If a line is parallel to another line, the only thing that's different in the equation is the y-intercept. Therefore we can solve for the y-intercept using the point (4,4)...
Note that the slope-intercept equation is y=mx+b where b is the y-intercept and m is the slope. x and y are the x and y coordinate pairs.
y=2x+b
4=2(4)+b
4=8+b
b=-4
Therefore the equation of the line that is parallel to y=2x+4 and passes through (4,4) is...
y=2x-4
