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olganol [36]
3 years ago
15

What is the base in the expression 4 superscript 5? 4 5 9 20

Mathematics
2 answers:
AURORKA [14]3 years ago
6 0

Answer:

Step-by-step explanation:

4⁵

4 is the base.

Yuki888 [10]3 years ago
4 0

Answer:

\huge\colorbox{pink}{An§wer}

4⁵

4 is the base

<u>Hope it helps </u>( ꈍᴗꈍ)

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Solve f(-4) for f(x) = 7x - 4x
Strike441 [17]

Answer:

-12

Step-by-step explanation:

What you have to do is plug -4  into the function as a puzzle. So, replace all x with -4.

f(-4) = 7(-4) - 4(-4) = -28 + 16 = -12

8 0
2 years ago
A company's year-end data shows the following amounts. Current assets $65,000 Current liabilities $25,000 Net income $7,500 Net
lozanna [386]

The company's current ratio is 2.6.

<h3>What is the current ratio?</h3>

Current ratio is an example of a liquidity ratio. Liquidity ratios are financial ratios measure a firm's ability to honour its short terms obligations.

Current ratio = current asset /current liability

$65,000 / 25,000 = 2.6

To learn more about current ratio, please check: brainly.com/question/19579866

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4 0
2 years ago
Simplify it plzzzzz and thx
frozen [14]

Answer:

this q is on quizizz

Step-by-step explanation:

5 0
3 years ago
USA TEST PREP PLS HELP
Kay [80]

Answer:

Coplanar

Step-by-step explanation:

That is the definition of Coplanar Points (or lines): points (line) that lie in the same plane.

4 0
3 years ago
Read 2 more answers
Am I correct on question #6?
pashok25 [27]

Option A:

\tan(105^\circ)=-(2+\sqrt{3})

Solution:

<u>To evaluate tan(105)°:</u>

105° can be written as sum of 60° and 45°.

tan(105)° = tan(45 + 60)°

Using the summation identity:

$\tan (x+y)=\frac{\tan (x)+\tan (y)}{1-\tan (x) \tan (y)}

$\tan \left(105^{\circ}\right)=\frac{\tan \left(45^{\circ}\right)+\tan \left(60^{\circ}\right)}{1-\tan \left(45^{\circ}\right) \tan \left(60^{\circ}\right)}

We know that, tan(45)° = 1 and tan(60)° = √3

Substitute this in the above equation.

              $=\frac{1+\sqrt{3}}{1-1 \cdot \sqrt{3}}

              $=\frac{1+\sqrt{3}}{1-\sqrt{3}}

To rationalize the denominator multiply by the conjugate \frac{1+\sqrt{3}}{1+\sqrt{3}}.

              $=\frac{(1+\sqrt{3})(1+\sqrt{3})}{(1-\sqrt{3})(1+\sqrt{3})}

Using exponent formula: a^{b} \cdot a^{c}=a^{b+c} and (x-y)(x+y)=x^2-y^2

              $=\frac{(1+\sqrt{3})^2}{(1^2-(\sqrt{3})^2)}

Using exponent formula: (a+b)^{2}=a^{2}+2 a b+b^{2}

              $=\frac{1^{2}+2 \cdot 1 \cdot \sqrt{3}+(\sqrt{3})^{2}}{1-3}

              $=\frac{4+2 \sqrt{3}}{-2}

              $=\frac{2(2+ \sqrt{3})}{-2}

              =-(2+\sqrt{3})

\tan(105^\circ)=-(2+\sqrt{3})

Hence option A is the correct answer.

6 0
4 years ago
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