All categories

2 years ago

2x^2 + 9x + 4 = 0 PLEASE HELP! I WILL MARK AS BRAINLIEST

Mathematics

2 answers:

babymother [125]2 years ago

8 0

Answer:

Step-by-step explanation:

Multiply co efficient of the x^2 and the constant; which will be 8

What can you multiply together that will give you 8 and add that give the co efficient of x, 9

1*8 ✓

(2x^2 +8x) + (1x + 4) = 0

Factorise

2x(x+4) +1(x+4) = 0

2x+1= 0

x+4=0

x = -1/2 or -4

Karo-lina-s [1.5K]2 years ago

4 0

(2x+1)(x+4)

calculator

You might be interested in

455 sofas in 48 hours graphed

GaryK [48]

Is there anymore details to this?

5 0

3 years ago

Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th

HACTEHA [7]

Answer:

Required equation of tangent plane is $z=\frac{6}{5}(x-5y-11)$ .

Step-by-step explanation:

Given surface function is,

$f(x,y)=6-\frac{6}{5}(x-y)$

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

$z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)$

So that,

$f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}$

$f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}$

$f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6$

Substitute all these values in (1) we get,

$z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}$

$\therefore z=\frac{6}{5}(x-5y-11)$

Which is the required euation of tangent plane.

4 0

2 years ago

What is tan 330°? for algebra 2 with trig in it.

Alekssandra [29.7K]

Tan (330) = 0.133557

8 0

3 years ago

Find x. Assume that segments that appear tangent are tangent.

kipiarov [429]

Assuming that CB is tangent, this is just a right triangle with a hypotenuse of 20 and a side of 12 so by the Pythagorean Theorem:

20^2=12^2+x^2

400=144+x^2

x^2=400-144

x^2=256

x=16

6 0

2 years ago

Eliza volunteers at a nearby aquarium

pishuonlain [190]

It is 3٫100 miles right

8 0

2 years ago