Answer:
vertical asymptote at x = 7
horizontal asymptote at y = 6
Step-by-step explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.
solve:
x
−
7
=
0
⇒
x
=
7 is the asymptote
Horizontal asymptotes occur as
lim
,f(x)→
c(a constant)
x
→
±
∞
divide terms on numerator/denominator by x
f
(
x
)
=
5/
x
+6=
5
/x
+
6
x/
x
−
7
/x 1
−
7/
x
as
x
±
∞
,
f
(
x
)
→
0
+6
1
−
0
⇒
y
=
6 is the asymptote
graph{((5)/(x-7))+6 [-20, 20, -10, 10]}
Answer:
15 square units
Step-by-step explanation:
5*3=15
Answer:
(- 9, - 9)
Step-by-step explanation:
Given the 2 equations
3x - 4y = 9 → (1)
- 3x + 2y = 9 → (2)
Adding (1) and (2) will eliminate the term in x
(1) + (2) term by term
(3x - 3x) + (- 4y + 2y) = (9 + 9)
0 - 2y = 18
- 2y = 18 ( divide both sides by - 2 )
y = - 9
Substitute y = - 9 into (1) or (2) and evaluate for x
(1) → 3x + 36 = 9 ( subtract 36 from both sides )
3x = - 27 ( divide both sides by 3 )
x = - 9
Solution is (- 9, - 9)
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