Answer:
f(x) = -(x-3)^2 + 4
Step-by-step explanation:
(h; k) are the coordinates of the vertex.
On the graph are (3, 4), therefore we have:
f(x) = a(x-3)^2 + 4
We have the x- intercept (1,0) -> x=1; y=0.
Substitute them into the equation:
0 = a(1 - 3)^2 + 4
0 = a(-2)^2 + 4
4a + 4 = 0 | -4
4a = -4 |-4
a = -1
So, we have the answer:
f(x) = -(x-3)^2 + 4
Its 2 8/15 Conversion a mixed number 1 2
5
to a improper fraction: 1 2/5 = 1 2
5
= 1 · 5 + 2
5
= 5 + 2
5
= 7
5
To find new numerator:
a) Multiply the whole number 1 by the denominator 5. Whole number 1 equally 1 * 5
5
= 5
5
b) Add the answer from previous step 5 to the numerator 2. New numerator is 5 + 2 = 7
c) Write previous answer (new numerator 7) over the denominator 5.
One and two fifths is seven fifths
Conversion a mixed number -1 2
15
to a improper fraction: -1 2/15 = -1 2
15
= -1 · 15 + (-2)
15
= -15 + (-2)
15
= -17
15
To find new numerator:
a) Multiply the whole number -1 by the denominator 15. Whole number -1 equally -1 * 15
15
= -15
15
b) Add the answer from previous step -15 to the numerator 2. New numerator is -15 + 2 = -13
c) Write previous answer (new numerator -13) over the denominator 15.
Minus one and two fifteenths is minus thirteen fifteenth
Subtract: 7
5
- (-17
15
) = 7 · 3
5 · 3
- (-17)
15
= 21
15
- (-17
15
) = 21 - (-17)
15
= 38
15
The common denominator you can calculate as the least common multiple of the both denominators - LCM(5, 15) = 15. The fraction result cannot be further simplified by cancelling.
In words - seven fifths minus minus seventeen fifteenth = thirty-eight fifteenths.
Answer:
x=-1
Step-by-step explanation:
Answer:
$129
Step-by-step explanation:
We need to find 15% of $860.
15% of $860 =
= 15% * $860
= 0.15 * $860
= $129
Answer:
The Null hypothesis is a claim the researcher is trying to disprove. (I think)
Step-by-step explanation:
The null hypothesis states that there is no relationship between the two variables being studied (one variable does not affect the other). It states results are due to chance and are not significant in terms of supporting the idea being investigated.