Answer:
e^ (5 ln (x + 1)) = (x + 1)^5
Step-by-step explanation:
e5 In (x + 1) or did you mean e^ (5 ln (x + 1))
because then this would simplify a lot
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5)
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5) = (x + 1)^5
or did you mean (e^5) ( ln (x + 1)) = ln [(x+1)^(e^5)]
But I think you meant:
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5) = (x + 1)^5
C more than 5 as an algebraic expression c>5
The value of m<span> must be greater than the value of</span><span> n</span><span>. When you multiply the binomials, the middle term is the result of combining the outside and inside products. So, </span>bx<span> = –</span>nx<span> + </span>mx<span>, or </span>bx<span> = (–</span>n<span> + </span>m)x<span>. This means that </span>b<span> = –</span>n<span> + </span>m<span>. When adding numbers with opposite signs, you subtract their absolute values, and keep the sign of the number having the larger absolute value. Since </span>b<span> is positive, </span>m<span>must have the larger absolute value.</span>
