Answer:
For a height of 66 inches, Z = 0.65.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The average height was about 64.3 inches; the SD was about 2.6 inches.
This means that
66 inches:
The z-score for a height of 66 inches is:
For a height of 66 inches, Z = 0.65.
15 = 80% * x
15 = 80/100 * x
15 = 8/10 * x
x = 15 * 10/8
x = 150/8
x = 18.75
<span>80% of 18.75 is </span>15<span>.</span>
7x-55/40-x = 1/2
14x-110 = 40-x
15x = 150
x = 10
GJ = 40-x = 40-10 = 30
Answer:
x = 3
Step-by-step explanation:
6x+ 5 = 3x + 14
Subtract 3x from both sides
6x+ 5 -3x = 3x + 14 - 3x
Simplifying
3x + 5 = 14
Subtract 5 from both sides
3x + 5 - 5 = 14 - 5
Simplifying
3x = 9
Divide both sides by 3
3x/3 = 9/3
Simplifying
x = 3
<span>First of all, write these in a way people can read them in the future. Don't make it so hard to help you.
Secondly:
Given that a♥b = 2a(32− b)
If a♥b = −23, solve for b in terms of a.
A) b = 16a + 32
B) b = 13a + 32
C) b = 12a + 32
D) b = 16a − 32
</span>-23 = 2a(32− b), devide both sides by 2a -23/2a = 32 - b, subtract 32 from both sides -23/2a - 32 = -b, multiply both sides by -1 23/2a + 32 = b
verified:
b = 23/2a + 32
-23 = 2a(32 − (23/2a + 32))
-23 = 2a(32 -23/2a -32)
-23 = 2a(-23/2a)
-23 = -23
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