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lubasha [3.4K]
3 years ago
14

I'm kinda stuck on this problem, help please???​

Mathematics
2 answers:
erastova [34]3 years ago
4 0
Number 2 is in box 3, 1 is in box 2, 3 is in box 3, 4 is in box 2, 5 is in box 1, 6 is in box 3
Aleksandr [31]3 years ago
4 0

Answer:

No Solution:

Top Middle

Top Right

One Solution:

Top Left

Bottom Left

Bottom Middle

Infinite:

Bottom Right

Explanation:

I will show one of each as an example for you to use. Here is the first one, it has one solution because it has a value for both x and y.

Let's solve your system by substitution.

−8x−10y=24;6x+5y=2

Solve−8x−10y=24 for x:

−8x−10y=24

−8x−10y+10y=24+10y(Add 10y to both sides)

−8x=10y+24

−8x−8=10y+24−8(Divide both sides by -8)

x=−54y−3

Substitute−54y−3 for x in6x+5y=2:

6x+5y=2

6(−54y−3)+5y=2

−52y−18=2(Simplify both sides of the equation)

−52y−18+18=2+18(Add 18 to both sides)

−52y=20

−52y−52=20−52(Divide both sides by (-5)/2)

y=−8

Substitute−8 for y in x=−54y−3:

x=−54y−3

x=−54(−8)−3

x=7(Simplify both sides of the equation)

Answer:

x=7 and y=−8

Next, a no solution problem. We will use the second system of equations.

Rewrite equations:

−x+y=3;−3x+3y=4

Solve−x+y=3 for y:

−x+y=3

−x+y+x=3+x(Add x to both sides)

y=x+3

Substitute x+3 for y in−3x+3y=4:

−3x+3y=4

−3x+3(x+3)=4

9=4(Simplify both sides of the equation)

9+−9=4+−9(Add -9 to both sides)

0=−5

This is not possible. Thus, there is no solution.

Lastly, a infinite solution problem. We will use the last system.

Solve 2x+8y=6 for x:

2x+8y=6

2x+8y+−8y=6+−8y(Add -8y to both sides)

2x=−8y+6

2x2=−8y+62(Divide both sides by 2)

x=−4y+3

Substitute −4y+3 for x in−5x−20y=−15:

−5x−20y=−15

−5(−4y+3)−20y=−15

−15=−15(Simplify both sides of the equation)

−15+15=−15+15(Add 15 to both sides)

0=0

It is equal, meaning that there are infinite solutions.

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SECOND TIME ASKING PLS HELP: A multiple choice question has 3 options. What is the percentage that you will chose the WRONG opti
DiKsa [7]

Answer:

2/3 or 66.67%

Step-by-step explanation:

2 wrong options, 3 total options. 2 over 3.

<em>Big Brain</em>

Hope this helps!! :)

5 0
3 years ago
Read 2 more answers
Suppose that administrators of a large school district wish to estimate the proportion of children in the district enrolling in
11Alexandr11 [23.1K]

Answer:

95% z-confidence interval for the proportion of all children enrolled in kindergarten who attended preschool is between a lower limit of 0.528 and an upper limit of 0.772.

Step-by-step explanation:

Confidence interval = p + or - zsqrt[p(1-p) ÷ n]

p is sample proportion = 39/60 = 0.65

n is the number of children sampled = 60

Confidence level (C) = 95% = 0.95

Significance level = 1 - C = 1 - 0.95 = 0.05

Divide significance level by 2 to obtain critical value (z)

0.05/2 = 0.025 = 2.5%

z at 2.5% significance level = 1.96

zsqrt[p(1-p) ÷ n] = 1.96sqrt[0.65(1-0.65) ÷ 60] = 1.96sqrt[0.2275 ÷ 60] = 1.96sqrt(3.792×10^-3) = 1.96×0.062 = 0.122

Lower limit = p - 0.122 = 0.65 - 0.122 = 0.528

Upper limit = p + 0.122 = 0.65 + 0.122 = 0.772

95% confidence interval is between 0.528 and 0.772

5 0
3 years ago
L'Shonda purchased a container of juice
cupoosta [38]

L'Shonda purchased a container of juice. 80 calories are from carbohydrates.

<u>Solution:</u>

Given that, LShonda purchased a container of juice that contains 200 calories.  

The label says that 40% of the calories are from carbohydrates.  

We have to find how many calories are from carbohydrates?

Now, according to the given information,

<em>Number of calories from carbohydrates = 40% of the total calories of the juice </em>

Then, calories from carbohydrates = 40% of 200 calories

40% can be written in fraction as \frac{40}{100}

\text { Calories from carbohydrates }=\frac{40}{100} \times 200=40 \times 2=80 \text { calories }

Hence, 80 calories are from carbohydrates.

5 0
3 years ago
Helpppppppppppppppppppppp
Naddika [18.5K]

Answer:

-6

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The angle of elevation to the top of a very tall building is found to be 13° from the ground at a distance of 1 mi from the base
Marta_Voda [28]
Tan(Θ)=(h/distance from base)
Θ=13 degrees, 1mile=5280 ft
tan(13)=(h/5280 ft)
5280tan(13)=h
h=1218.984049
h=1219 ft
4 0
3 years ago
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