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nasty-shy [4]
3 years ago
14

Whats The Answer Marking Brainliest, Please explain your answer:D.......

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0

Answer:

D

Step-by-step explanation:

It is given in ratio and looks correct.

Ymorist [56]3 years ago
5 0

Answer:

D

Step-by-step explanation:

D is the only answer given as a ratio, the rest are not.

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(3p^3-21p^2 + 26p +24)÷p-5)​
denpristay [2]

Answer:

(3p^3-21p^2=26p=24/p)-5

Step-by-step explanation:

5 0
3 years ago
HELP ME RNRNRN I WIll give brainlist
Sliva [168]

Answer:

5^2=25, so a=5

Step-by-step explanation:

3 0
3 years ago
3^-6 x (3^4 / 3^0)^2
inna [77]

Answer:

9 x

Step-by-step explanation:

Simplify the following:

((3^4/3^0)^2 x)/(3^6)

Hint: | Compute 3^6 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

3^6 = (3^3)^2 = (3×3^2)^2:

((3^4/3^0)^2 x)/((3×3^2)^2)

Hint: | Evaluate 3^2.

3^2 = 9:

((3^4/3^0)^2 x)/((3×9)^2)

Hint: | Multiply 3 and 9 together.

3×9 = 27:

((3^4/3^0)^2 x)/(27^2)

Hint: | Evaluate 27^2.

| 2 | 7

× | 2 | 7

1 | 8 | 9

5 | 4 | 0

7 | 2 | 9:

((3^4/3^0)^2 x)/729

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to 3^4/3^0.

Combine powers. 3^4/3^0 = 3^(4 + 0):

((3^4)^2 x)/729

Hint: | For all positive integer exponents (a^n)^m = a^(n m). Apply this to (3^4)^2.

Multiply exponents. (3^4)^2 = 3^(4×2):

(3^(4×2) x)/729

Hint: | Multiply 4 and 2 together.

4×2 = 8:

(3^8 x)/729

Hint: | Compute 3^8 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

3^8 = (3^4)^2 = ((3^2)^2)^2:

(((3^2)^2)^2 x)/729

Hint: | Evaluate 3^2.

3^2 = 9:

((9^2)^2 x)/729

Hint: | Evaluate 9^2.

9^2 = 81:

(81^2 x)/729

Hint: | Evaluate 81^2.

| | 8 | 1

× | | 8 | 1

| | 8 | 1

6 | 4 | 8 | 0

6 | 5 | 6 | 1:

(6561 x)/729

Hint: | In (x×6561)/729, divide 6561 in the numerator by 729 in the denominator.

6561/729 = (729×9)/729 = 9:

Answer:  9 x

3 0
3 years ago
Read 2 more answers
On a coordinate plane, a straight red line with a negative slope, labeled g of x, crosses the y-axis at (0, negative 7). A strai
emmainna [20.7K]

Answer:

f(-3)=g(-3)

Step-by-step explanation:

The graph shows two linear functions that intersect at (-3,-4).

The blue line is f(x).

At the point of intersection:

f(-3)=-4....eqn1

The blue line is g(x).

At the point of intersection

g(-3)=-4....eqn2

Equating both equations we get:

f(-3)=g(-3)

The statement that is true regarding the two functions is that:

f(-3)=g(-3)

8 0
4 years ago
Read 2 more answers
Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
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