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2 years ago

Whats The Answer Marking Brainliest, Please explain your answer:D.......

Mathematics

2 answers:

ICE Princess25 [194]2 years ago

7 0

Answer:

Step-by-step explanation:

It is given in ratio and looks correct.

Ymorist [56]2 years ago

5 0

Answer:

Step-by-step explanation:

D is the only answer given as a ratio, the rest are not.

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Solve the following inequality. 21<_-3(x - 4) < 30 A. 28<_x < 37 B. -3 <_ x < 6 C. -6 < x <_ -3 D. -10 &

Aloiza [94]

Answer:

Option C $-6$

Step-by-step explanation:

we have

$21\leq -3(x-4)$

The compound inequality can be divided into two inequality

$21\leq -3(x-4)$ -----> inequality A

$-3(x-4)$ ----> inequality B

Solve inequality A

$21\leq -3x+12$

$9\leq -3x$

Divide by -3 both sides

when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$-3\geq x$

Rewrite

$x\leq -3$

The solution of the inequality A is the interval (-∞,-3]

Solve the inequality B

$-3x+12$

$-3x$

Divide by -3 both sides

when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$x>-6$

The solution of the inequality B is the interval [-6,∞)

The solution of the compound inequality is

[-6,∞) ∩ (-∞,-3]=(-6,-3]

$-6$

3 0

3 years ago

Helpppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Oliga [24]

Answer: the answer is A the slop is 1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If p is inversely proportional to the square of q, and p is 25 when q is 3, determine p

ArbitrLikvidat [17]

Answer:

p = 9 when q = 5.

Step-by-step explanation:

p is inversely proportional to the square of q

This means that:

$p = \frac{k}{q^2}$

In which k is a constant multiplier.

p is 25 when q is 3

We use this to find k.

$p = \frac{k}{q^2}$

$25 = \frac{k}{3^2}$

$k = 25*9 = 225$

$p = \frac{225}{q^2}$

Determine p when q is equal to 5.

$p = \frac{225}{q^2} = \frac{225}{5^2} = 9$

p = 9 when q = 5.

6 0

2 years ago

There's got to be someone who can answer this

Sphinxa [80]

Yes based on ja 82 and it can be added

4 0

3 years ago

What is the radius of convergence of the maclaurin series (2x)/(1+x^2)?

kramer

To solve this problem you must apply the proccedure shown below:
1. You have to find the radius <span>of convergence of the following Maclaurin series:
</span> $(2x)/(1+ x^{2} )
$
2. Let's take the denominator and find the roots:
$1+ x^{2} =0$
$x^{2} =-1 \\ x= \sqrt{-1} \\ x1=i \\ x2=-i$
3. The roots are $x1=i \\ x2=-i$ and the distance from the origin is $1$ .
Therefore, the answer is: $1$

7 0

2 years ago