So, let's make these two values improper fractions so they're easier to work with. 
So, to get the rate he grew in those months we have:
And to get the rate he grew in one month we have to divide both our numerator and our denominator by 21 to get:
aka he grew 1.24 inches in a month.
Answer:
b) -4
Step-by-step explanation:
Well your at 2 and going to -2 so on a number line you be going back or left.
Going two left gets you to zero and going two more get you -2. So in total you went back four and that be represented as -4.
Kepler's third law described the relation between semi-major axis (or average distance to the star) and
the orbital period (how long it takes to complete one lap) as follows:
a^3 / p^2 = constant
In the case of our Solar system the constant is 1
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU
Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
128 inches
for area , you multiply length times height so it’d be 16 x 8 :)
3.1 (it is the tenth place)
