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3 years ago

Log3 27=3x+6 solve this please

Mathematics

2 answers:

kodGreya [7K]3 years ago

5 0

$log_327=3x+6\\\\log_33^3=3x+6\\\\3=3x+6\\\\-3x=6-3\\\\-3x=3\ /:(-3)\\\\x=-1$

statuscvo [17]3 years ago

4 0

$log_327=3x+6\\\\log_33^3=3x+6\\\\3=3x+6\\\\3x+6=3\ \ \ /-6\\\\3x=-3\ \ \ /:3\\\\x=-1$

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Solve the equation. 2x+1/3+x-1/4=13/2

inessss [21]

The solution of the equation is x = 71 / 36.

<h3>How to solve an equation with one variable</h3>

Herein we have an equation with several rational constants and only one variable, x, which has to be cleared by using algebra procedures. The procedure is shown below:

2 · x + 1 / 3 + x - 1 / 4 = 13 / 2 Given

2 · x + x = 13 / 2 - 1 / 3 - 1 / 4 Compatibility with addition / Existence of additive inverse / Modulative property

3 · x = 71 / 12 Definitions of addition and subtraction / Distributive property

x = 71 / 36 Compatibility with multiplication / Existence of multiplicative inverse / Modulative property / Result

The solution of the equation is x = 71 / 36.

To learn more on equations: brainly.com/question/10413253

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4 0

1 year ago

Leila says that 75% of a number will always be greater than 50% of any other number. Complete one inequality to support Leilas c

Greeley [361]

If a number is positive, Leila's theory that 75% of a number will always be greater than 50% of another number is <em>true</em>;<em> </em>however, if both numbers are negative, or if the number of which she finds 50% is much greater than the number of which she finds 75%, Leila's theory could be incorrect.

This inequality shows that Leila is correct: $100(0.75) \geq 50(0.50)$ (which simplifies to $75 \geq 25$ )

This inequality shows that Leila is incorrect: $50(0.75) \geq 100(0.50)$ (which simplifies to $37.5 \geq 50$ )

Hope this helps!

6 0

2 years ago

Read 2 more answers

A farmer has both pigs and chickens on his farm there are 78 fee and 27 heads how many pigs and how many chickens are there

Andre45 [30]

Assuming health non-mutated animals:
$Feet = 4*Pigs + 2*Chickens$
$Heads = Pigs + Chickens$

By back substitution:
$78 = 4*(27-Chickens) + 2*Chickens$
$78 = 108 -2*Chickens$
$-30 = -2*Chickens$
$Chickens= 15$

Then:
$27 = Pigs + 15$
$Pigs = 12$

To check:
$Feet = 4*Pigs + 2*Chickens$
$78 = 4*12 + 2*15$
$78 = 48 + 30$
$78 = 78$ CHECKS

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3 years ago

How do you solve x3 (y-5) (x-8) (the numbers next to the variables (letters) are supposed to be exponents)

Galina-37 [17]

Y^-5
x^-5
because you have to put together all the x and then put all the y's together

7 0

3 years ago

How do I solve these problems?

lesya [120]

$Domain:\\D:x > 0\\\\\ln x=5.6+\ln(7.5)\ \ \ \ |-\ln(7.5)\\\\\ln x-\ln7.5=5.6\ \ \ |Use\ \log x-\log y=\log\dfrac{x}{y}\\\\\ln\dfrac{x}{7.5}=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\\dfrac{x}{7.5}=e^{5.6}\ \ \ \ |\cdot7.5\\\\\boxed{x=7.5e^{5.6}}\in D$

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5 0

2 years ago