By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
<h3>How to determine the maximum height of the ball</h3>
Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:
- 4.8 · t² + 19.9 · t + (55.3 - h) = 0
The height of the ball is a maximum when the discriminant is equal to zero:
19.9² - 4 · (- 4.8) · (55.3 - h) = 0
396.01 + 19.2 · (55.3 - h) = 0
19.2 · (55.3 - h) = -396.01
55.3 - h = -20.626
h = 55.3 + 20.626
h = 75.926 m
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
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2 - 12 + 18
= -10 + 18
= 8
The answer is D.
Line M with slope 6 is neither, line n with slope -6 is parallel because only lines with same slope are parallel, line p with slope 1/6 is neither. and line q with slope -1/6 is perpendicular because only the reciprocal of a slope is perpendicular, so reciprocal of 6= 1/6 reciprocal of -6=-1/6 reciprocal of 2= 1/2
For this case we have the following fractions:
We must rewrite the fractions, using the same denominator.
We have then:
We multiply the first fraction by 11 in the numerator and denominator:
We multiply the second fraction by 2 in the numerator and denominator:
Rewriting we have:
For the first fraction:
For the second fraction:
We note that:
Answer:
The fractions are not equivalent:
Answer:
C
Step-by-step explanation:
y=1/x, the reciprocal is the same. Reciprocal would be reflected across y=x
