How many minutes did it take him to cover 1 mile? 5 minutes.
Answer: x < 11.9
Step-by-step explanation:
Answer:
- m∠A ≈ 53.13°
- m∠B ≈ 73.74°
- m∠C ≈ 53.13°
Step-by-step explanation:
An altitude to AC bisects it and creates two congruent right triangles. This lets you find ∠A = ∠C = arccos(6/10) ≈ 53.13°.
Since the sum of angles of a triangle is 180°, ∠B is the supplement of twice this angle, so is about 73.74°.
m∠A = m∠C ≈ 53.13°
m∠B ≈ 73.74°
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The mnemonic SOH CAH TOA reminds you of the relation between the adjacent side, hypotenuse, and trig function of an angle:
Cos = Adjacent/Hypotenuse
If the altitude from B bisects AC at X, triangle AXB is a right triangle with side AX adjacent to the angle A, and side AB as the hypotenuse. AX is half of AC, so has length 12/2 = 6, telling you the cosine of angle A is AX/AB = 6/10.
A diagram does not have to be sophisticated to be useful.
In triangle ABC and DEF
AC =DF, [ given ]
AB =DE, [ given ]
angle A = angle D
by SAS
ABC congruent to triangle DFE
so
BC = EF, [ CPCTC]
hence proved
1. A. y and 1.2y are like terms. c they both contain the same term (y) and can therefore be combined.
2. B. 12x+11 (you have to combine the like terms)
3. 15y+18-4
C. 15y+14 (you must distribute the 3 to inside the parentheses, so 3×5y and 3×6)
4. 9(9-3p) (you have to find a common factor between the terms, in this case 9, and you place it on the outside of the parentheses, while dividing that factor from those terms, which are placed in parentheses.