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nika2105 [10]
3 years ago
15

Eric wants to get an output of 0. Can he do this with each machine? If so, how? If not, why not?

Mathematics
1 answer:
natita [175]3 years ago
4 0

Answer:

  • <u>No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).</u>

Explanation

The way each machine works is given by the expression (function) inside it.

<u>1)  </u><em><u>Function A</u></em>

To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.

Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.

<u>2) </u><em><u>Function B</u></em>

Solve y=\sqrt{x}-2=0

  • \sqrt{x}-2=0

  • \sqrt{x} =2

  • x=2^{2}

  • x=4

So, he can get an output of 0 by using x = 4.

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Given the system of linear equations.
Karo-lina-s [1.5K]

Part A:


x + y = 9

4x + y = 6


To solve this system using substitution, begin by isolating either x or y in the first equation. I'll isolate x.


x + y = 9

x = 9 - y


Substitute this expression (9 - y) into the second equation for x and solve.


4x + y = 6

4(9 - y) + y = 6

36 - 4y + y = 6

36 - 3y = 6

-3y = -30

y = 10


To find x, substitute 10 for y into either of the original equations.


x + y = 9

x + 10 = 9

x = -1


Finally, check all work by substituting the x- and y-values into each original equation.


x + y = 9   -->   -1 + 10 = 9   -->   9 = 9   -->   True

4x + y = 6   -->   4(-1) + 10 = 6   -->   -4 + 10 = 6   -->   6 = 6   -->   True


The answer for Part A is x = -1 and y = 10; (-1, 10).


Part B:


For graphing, it's easier to get the equations into slope-intercept form. Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. To get our equations into slope-intercept form, we must simply isolate y.


x + y = 9

y = 9 - x

y = -x + 9


4x + y = 6

y = 6 - 4x

y = -4x + 6


Now that we have our slope-intercept equations, we can easily graph them, since their slopes and y-intercepts are readily visible.



Let's start with the y-intercepts. They are (0, 9) and (0, 6). You can plot those points on the graph.


Now, the slopes. The slope of the first line is -1, this means it declines. To plot this, start where you plotted the y-intercept, count one unit down, and then one unit to the right, and plot that point. Continue doing that and connect the dots, and you will have plotted the first line. The slope of the second line is -4, so it also declines. For this line, count four units down, and then one to the right and plot that point. Likewise, continue this and connect the coordinates, and you will have your line. (See attachment for graph.)


The lines do indeed intersect at (-1, 10); our answer is verified by graphing.

5 0
3 years ago
*Will mark brainest!* Determine whether the guven equations are parallel, perpendicular or neither.
ioda

These are parallel lines

3 0
3 years ago
Find the solution set for this equation. Separate the two values with a comma.
adelina 88 [10]
Y^2 -11y = 0

We can factor it:
y * (y -11) = 0

So y = 11, 0


3 0
3 years ago
Read 2 more answers
Test the hypothesis using the P value approach. Be sure the verify the requirements of the test.
Andreas93 [3]

Answer:

p_v =2*P(z  

If we compare the p value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly different from 0.77.  

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X=380 represent the number of people with some characteristic

\hat p=\frac{380}{500}=0.76 estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

p_o=0.76 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.7 .:  

Null hypothesis:p=0.77  

Alternative hypothesis:p \neq 0.77  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

<em>Check for the assumptions that he sample must satisfy in order to apply the test </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np_o =500*0.77=385>10

n(1-p_o)=384*(1-0.77)=115>10

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.76-0.77}{\sqrt{\frac{0.77(1-0.77)}{500}}}=-0.531  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

If we compare the p value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly different from 0.77.  

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4 years ago
A multiple must be greater than or equal to the largest starting number. True or False
podryga [215]

I'll use multiples of 2 and 4 as an example:

Multiples of 2: 2, 4, 6, 8...

Multiples of 4: 4, 8, 12, 16...

The least common multiple in this case is 4. The LCM is always ≥ the largest starting number, which is 4 for this example. Therefore, the statement is true.

<em>Hope this helps! :)</em>

8 0
4 years ago
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