The answer can be readily calculated using a single variable, x:
Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%
The problem is then stated as:
(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000
Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
(-5/3)•(-6/1)=(30/3)
(30/3) simplified is (10/1)
Answer:
1 1/4
Step-by-step explanation:
x=2, y=3, and z=1
1/2(2)+3/4(3)=1+3/12=1 1/4
Answer:
3m=9np
Step-by-step explanation:
3m-2-5np
+4 +4
3m=9np
9-2=?
-2
x-7
It is C (2, 1) I think it is because they intersect
