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Alexandra [31]
3 years ago
12

Need help with this asap!!

Mathematics
1 answer:
Bingel [31]3 years ago
7 0

Answer:

≈ 53.7° (Option 3)

Step-by-step explanation:

In the figure given above , the lengths of other two sides (excluding hypotenuse) are known to us. So , it would be convenient to use 'tan'.

Length of side opposite to angle 'x' = 15 cm

Length of side adjacent to angle 'x' = 11 cm

Using 'tan' formula - \tan x = \frac{Side \: opposite \: to \: x}{Side \: adjacent \: to \: x} , lets solve this.

=> \tan x = \frac{15}{11}

Using inverse tan function , lets find x.

=> x = {\tan}^{-1}(\frac{15}{11} ) ≈ 53.74°

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Answer:

See the proof below

Step-by-step explanation:

Let the line AB be a straight line on the parallelogram.

A dissection of the line (using the perpendicular line X) gives:

AY ≅ BX

Another way will be using the angles.

The angles are equal - vertically opposite angles

Hence the line  AY ≅ BX (Proved)

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3 years ago
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Answer:

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Step-by-step explanation:

The problem says that triangle BDC lies in the plane k, which means that whatever angle is formed by another point beyond this plane with any of the three segments that form BDC (BD, DC, and BC) is the same as the angle formed by the line connecting the point and the plane.

Here, we're given that AD⊥DC, which means AD forms a 90° angle with DC. Then, since DC is already on the plane, we already know for sure that AD is definitely perpendicular to plane k.

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3 years ago
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0.2(10-5c)=5c-16 halp
iogann1982 [59]

Answer:

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Step-by-step explanation:

0.2(10 -5c)= 5c -16

<em>Expand</em><em>:</em>

0.2(10) +0.2(-5c)= 5c -16

2 -c= 5c -16

<em>Bring</em><em> </em><em>all</em><em> </em><em>c</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>

5c +c= 2 +16

<em>Simplify</em><em>:</em>

6c= 18

<em>Divide</em><em> </em><em>by</em><em> </em><em>6</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

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Answer:

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The 2D shape at the ends of the prism is the base of the prism, so for this shape, the <u>bases</u> are the <u>triangles</u>.

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