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melisa1 [442]
3 years ago
6

Trig Ratios and Finding Missing Sides Notes

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

Answer:

G

Step-by-step explanation:

Ghgfhfgh of hgthhd yyuvd

siniylev [52]3 years ago
7 0

Answer:

https://faq.brainly.com/hc/en-us/articles/360014661139.

Step-by-step explanation:

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What is the solution of 1/3b = -3
Tcecarenko [31]
Simplify 1/3b to b/3

b/3 = -3


multiply both sides by 3

b = -3 * 3

multiply 3 * 3 so it can = 9

Answer: b = -9
5 0
3 years ago
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The output of a function or relation, or the set of y-values that a graph is defined for, is called the ___.
Andre45 [30]

Answer:

Range

Step-by-step explanation:

The range of a graph tells you <u>all of the possible y-values</u> for it.

There is also the domain, which tells you all of the possible x-values.

For example, if you have this relation, that only has these points:

(1, 2) (2, 4) (3, 6)

Then the range is {2, 4, 6}. This means the "y" can ONLY be the numbers stated here.

The domain would be {1, 2, 3}.

3 0
3 years ago
The ratio of boys and girls in the school musical is 5 to 8.Which of the following shows the possible numbers of boys and girls
Maurinko [17]

Answer:

I don't see the following ratios.

Step-by-step explanation:

I think you should add the following.

6 0
3 years ago
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Find the sum or difference.
KIM [24]

Answer:

the sum of the given matrices is

-7 -2

4 -15

6 0
3 years ago
Estimate 1 13 cos(x2) dx 0 using the Trapezoidal Rule and the Midpoint Rule, each with n = 4. (Round your answers to six decimal
babunello [35]

Answer:

(a) 4.152698

(b) 3.215557

Step-by-step explanation:

(a)

\int\limits^{13}_1 {cos(x^2)} \, dx =M_n=$\sum_{n=1}^{\infty} f(m_i)\Delta x $

n=4, so :

Each subinterval has length :

\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

Now, the midpoints of these subintervals are:

\frac{1+5}{2} =3\\\\\frac{5+9}{2} =7\\\\\frac{9+13}{2} =11

Hence:

M_4= 3*(cos(3^2))+3*(cos(7^2))+3*cos((11^2))\approx 4.152698

(b)

\int\limits^{13}_1 {cos(x^2)} \, dx =T_n=\frac{\Delta x}{2} (f(x_o)+2f(x_1)+2f(x_2)+...+2f(x_n_-_1)+f(x_n))

n=4, so :

Each subinterval has length :

\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

The endpoints of the subintervals consist of:

5,9

Hence:

T_4= \frac{3}{2}(cos(1^2)+2*cos(5^2)+2*cos(9^2)+cos(13^2)) \approx 3.215557

8 0
3 years ago
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