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Keith_Richards [23]
2 years ago
6

Which statement is true about the interval from 40 to 50 minutes?

Mathematics
2 answers:
never [62]2 years ago
6 0

Answer:

A

Step-by-step explanation:

mezya [45]2 years ago
3 0
The answer to that questions is A
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Macy's store received an order of 75 baseball caps of which nine were green if one of the 75 caps is selected at random, what is
Helga [31]
Less likely
because 5 is green you might pick one but more  likey you wont
6 0
3 years ago
The sum of three consecutive odd numbers is 63. What is the smallest of these numbers?
vovangra [49]

x+x+2+x+4=63

3x+6=63

3x=57

x= 19 smallest number



4 0
2 years ago
Read 2 more answers
The populations of termites and spiders in a certain house are growing exponentially. The house contains 120 termites the day yo
zysi [14]

Answer:

in order to triple the inicial population of spiders, will take 50395 days

Step-by-step explanation:

we can define the termite population function as T(t) and the one for spiders as S(t) , where t represents time measured in days

since both have and exponencial growth

T(t)= a*e^(b*t)

S(t)= c*e^(d*t)

1) when the day the person moves in , t=0 and T(0)= 120 termites

T(0) = a*e^(b*0) = a = 120

2) after 4 days , t=4 and  the house contains T(4) = 210 termites

T(4)= 120*e^(b*4) = 210 → 4*b = ln (210/120) → b = (1/4)* ln(210/120)= 0.14

therefore

T(t) = 120*e^(0.14*t)

3) 3 days after moving in , t=3, there were T(3) = 120*e^(0.14*3)=182.63≈ 182 termites . The number of spiders is half of the number of termites → S(3) = T(3) * 1 spider/ 2 termites  =91.31 spiders ≈ 91 spiders

4) after 8 days of moving in , t=8, there were T(8) = 120*e^(0.14*8)=367.78≈ 368 termites . The number of spiders is 0.25 times the number of termites → S(8) = T(8) * 1 spider/ 4 termites =91.94 spiders   ≈ 92 spiders

from

S(t)= c*e^(d*t) → d = ln [S (tb)/S (ta) ] / (tb-ta)

therefore d = ln [ S(8)/S(3) ] / (8 - 3 ) = 2.18*10^-5

in order to triple the initial population

S(t3) = 3 *S(0) = 3*[c*e^(d*0)] = 3*c

S(t3) = c*e^(d*t3) = 3* c → t3 = ln(3) / d = 50395 days

5 0
3 years ago
Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon
motikmotik

Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

  • Simon has more money than Kande

               S > K

  •  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

  • While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146

3 0
2 years ago
Jason ran 325 meters more than kim. kim ran 4.2 kilometers .how many meters did jason run?
vladimir1956 [14]
I know the answer: It is 329.2!!:)

8 0
3 years ago
Read 2 more answers
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