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2 years ago

14

A girl threw a marble 15 m vertically up in the air which later fell and settled at the bottom of a lake 7 m deep. Find the tota

l distance travelled by the marble while falling down?

1 answer:

emmasim [6.3K]2 years ago

6 0

Answer:

22 m

Step-by-step explanation:

Total distance travelled by marble while falling down = height above surface of lake + depth of lake = 15 + 7 = 22 m

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The points represented by the (x, y) coordinate pairs in the

77julia77 [94]

Step-by-step explanation:

For every increase in the x-value by 1,

the y-value decreases by -2.

(From 3 to 1 and from 1 to -1)

Hence, slope of line k

= Rise/Run = (-2)/1 = -2. (A)

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2 years ago

Y’all I need help I need a good grade on this

Andreyy89

Answer:

SLOPE IS -3

Step-by-step explanation:

4-7 over 0-(-1)

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2 years ago

Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from B, a distance o

g100num [7]

Answer:

The value is $k =109.6 \ miles$

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

The distance from city A to B is AB = 467.3 miles

The bearing from B to C is $\theta_{BC} = N 28.7E$

The bearing from B to A is $\theta_{BA} = N 60.7E$

The bearing from A to B is $\theta_{AB} = S60.7W$

The bearing from A to C is $\theta_{AC} = S79.1W$

Generally from the diagram

$\theta_A = 180 - 60.7 -79.1$

=> $\theta_A = 40.2 ^o$

Also

$\theta_B = 32^o$

and

$\theta_C = 180 - (\theta_A +\theta_B )$

=> $\theta_C = 180 - (40.2 + 32 )$

=> $\theta_C = 107.8 ^o$

Generally according to Sine Rule

$\frac{BC}{sin (\theta_A)} = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}$

=> $\frac{BC}{sin (40.2)} = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}$

So

$\frac{BC}{sin (40.2)} = \frac{467.3 }{sin (107.8)}$

=> $BC = 316.8 \ miles$

Also

$\frac{CA}{sin (32)} = \frac{467.3 }{sin (107.8)}$

$CA = 260 .1 \ miles$

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as

$k = [CA +BC] - AB$

=> $k = [260 .1 +316.8]- 467.3$

=> $k =109.6 \ miles$

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2 years ago

Question 1 Draw a line through the point (−2,−2) with a slope of 1/4. Draw a line through the point (2, 0) with a slope of 1/4.

Natasha2012 [34]

Answer:

line1： $y=\frac{1}{4}x-\frac{3}{2}$

line2: $y=\frac{1}{4}x -\frac{1}{2}$

Step-by-step explanation:

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2 years ago

Solve and state any extraneous solutions

Mice21 [21]

$\frac{3x}{x - 1} + 2 = \frac{3}{x - 1}$

$\frac{3x}{x - 1} + \frac{2(x - 1) }{ x - 1} = \frac{3}{x - 1}$

$\frac{3x}{x - 1} + \frac{2x - 2}{ x - 1} = \frac{3}{x - 1}$

$\frac{3x + 2x - 2}{ x - 1} = \frac{3}{x - 1}$

$3x + 2x - 2 = 3$

$5x - 2 = 3$

$5x = 3 + 2$

$5x = 5$

$x = \frac{5}{5}$

$x = 1$

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2 years ago